Momentum and movement basic GCSE Quest

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Homework Help Overview

The discussion revolves around a momentum problem involving Mr. Green, who steps off a boat, and the resulting motion of the boat. The participants explore the principles of momentum conservation in a system where two objects are initially at rest.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the initial conditions of the problem, questioning how to apply momentum conservation. There are attempts to clarify the definitions of momentum and the implications of directionality in the calculations. Some participants express confusion about the formulas needed to solve the problem.

Discussion Status

The discussion is ongoing, with participants providing hints and guidance regarding the momentum calculations. There is an exploration of different interpretations of the problem, particularly concerning the signs of momentum and the relationship between the velocities of Mr. Green and the boat.

Contextual Notes

Some participants note the lack of information regarding time or distance, which complicates the calculation of velocity. The discussion also highlights the importance of correctly applying vector principles in momentum calculations.

nonthesecond
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Mr Green, mass 80 kg, stepped off a boat of mass 35 kg at a speed of 3m/s. how fast did the boat move in the opposite direction?

i have no idea how to work it out?
 
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nonthesecond said:
Mr Green, mass 80 kg, stepped off a boat of mass 35 kg at a speed of 3m/s. how fast did the boat move in the opposite direction?

i have no idea how to work it out?

I think you will find that Mr Green and the boat are assumed to be at rest initially, so the total momentum was - and will remain - zero.
 
PeterO said:
I think you will find that Mr Green and the boat are assumed to be at rest initially, so the total momentum was - and will remain - zero.

ok thanks but how do i answer the question?
 
PeterO said:
I think you will find that Mr Green and the boat are assumed to be at rest initially, so the total momentum was - and will remain - zero.

i still don't understand i don't understand what formula to use as well.
 
nonthesecond said:
i still don't understand i don't understand what formula to use as well.

If you define the direction Mr Green goes as positive, he will have some positive momentum after he leaves the boat.
To maintain a total of zero, the boat must have an equal sized, but negative momentum - so it will be traveling at an appropriate speed in the negative direction (ie the other way)
 
PeterO said:
If you define the direction Mr Green goes as positive, he will have some positive momentum after he leaves the boat.
To maintain a total of zero, the boat must have an equal sized, but negative momentum - so it will be traveling at an appropriate speed in the negative direction (ie the other way)

i think i remeber my teacher saying that it's: 80 + 35= 115
115 x 3 = 375
375/35 = 1.3...m/s

is that correct?
 
nonthesecond said:
i think i remeber my teacher saying that it's: 80 + 35= 115
115 x 3 = 375
375/35 = 1.3...m/s

is that correct?

Sadly, no.

When you added the masses and multiplied by 3 (presumably the speed of Mr Green), you calculate the momentum if both he and the boat were traveling at that veocity; only he is.
 
nonthesecond said:
i think i remeber my teacher saying that it's: 80 + 35= 115
115 x 3 = 375
375/35 = 1.3...m/s

is that correct?

answer these in order:
What is Mr Green's mass?

What is Mr Green's velocity?

What is Mr Green's momentum?

What is the boat's momentum?

What is the boat's mass?

What is the boat's velocity?
 
PeterO said:
answer these in order:
What is Mr Green's mass?

What is Mr Green's velocity?

What is Mr Green's momentum?

What is the boat's momentum?

What is the boat's mass?

What is the boat's velocity?

you are very kind for helping me.

80kg

240 kg m/s

105 kg m/s

35kg

no idea for velocity i know formula is f=d/t but you aren't given time or distance.
 
  • #10
nonthesecond said:
you are very kind for helping me.

80kg correct

(+3) - but you didn't answer that question

+240 kg m/s almost correct

105 kg m/s incorrect

35kg correct

no idea for velocity i know formula is f=d/t but you aren't given time or distance.

For that final velocity - think about how you calculated the momentum of Mr Green - and don't forget to use + and - signs correctly.
Velocity is a vector; so can be positive or negative.

EDIT: Hint - answers 3 and 4 add up to zero
 
  • #11
PeterO said:
For that final velocity - think about how you calculated the momentum of Mr Green - and don't forget to use + and - signs correctly.
Velocity is a vector; so can be positive or negative.

EDIT: Hint - answers 3 and 4 add up to zero

is the answer 240/35?
 
  • #12
PeterO said:
For that final velocity - think about how you calculated the momentum of Mr Green - and don't forget to use + and - signs correctly.
Velocity is a vector; so can be positive or negative.

EDIT: Hint - answers 3 and 4 add up to zero

did i get the question right?
 
  • #13
nonthesecond said:
is the answer 240/35?

Certainly is.
 

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