Momentum and Spring Compression

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SUMMARY

This discussion focuses on analyzing elastic collisions involving vehicles striking a spring characterized by a spring constant (k). Participants explore the relationship between momentum, kinetic energy, and potential energy during maximum spring compression, using the equation 1/2mv² = 1/2kx². Key insights include the need for calculus to derive the time of maximum compression based on impulse and energy conservation principles. The conversation emphasizes the importance of understanding simple harmonic motion (SHM) to determine the time period and the fraction of time from maximum speed to maximum compression.

PREREQUISITES
  • Understanding of elastic collisions and momentum conservation
  • Familiarity with kinetic and potential energy equations
  • Basic calculus for deriving relationships between variables
  • Knowledge of simple harmonic motion (SHM) principles
NEXT STEPS
  • Study the derivation of the time period of simple harmonic motion from spring constant and mass
  • Learn about energy conservation in elastic collisions
  • Explore impulse-momentum theory and its applications
  • Investigate the relationship between maximum speed and maximum compression in elastic systems
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in the dynamics of elastic collisions and spring mechanics will benefit from this discussion.

Zaft3
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I am asked to rate a series of elastic collisions in order greatest time of max compression to least time of max compression for several vehicles with varying masses and velocities, which strike a spring with a spring constant k.



I can determine the Momentum of each case, as I am given the masses and velocities. Additionally, I can determine each of their kinetic energy.

I am working on the presumption that the kinetic energy of the car will be converted into potential energy in the spring:

1/2mv^2 =1/2kx^2

Also, I know the impulse of the car's is going to be

Ft= Δvm, so t=Δvm/F

I also know that the Force on spring will be F=kx, but I am not sure how the magnitude of the momentum of the car's is going to relate to the time of maximum spring compression.

Any hints?
 
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Hi Zaft3! Welcome to PF :smile:

I think you will need to use a bit of calculus. The impulsive force you need is only for the last instant when velocity becomes zero, and not through the whole compression of the spring. So, conserving energy you will get v' as,

[tex](V')^2 = \frac{mv^2-kx^2}{m}[/tex]

And, by impulse equation,

[tex]m\cdot dv' = k\cdot dt\cdot dx[/tex]

Differentiate the first equation with respect to x, and using that relation, integrate the second equation.
 
Zaft3 said:
I am asked to rate a series of elastic collisions in order greatest time of max compression to least time of max compression for several vehicles with varying masses and velocities, which strike a spring with a spring constant k.

From the instant the vehicle strikes the spring they move together till maximum compression, when the speed becomes zero, according to a simple harmonic motion.

Do you can find the time period of that SHM from the spring constant and the mass of the vehicle?

What fraction of the time period elapses from maximum speed to maximum compression (zero speed)?

ehild
 

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