Momentum ballistics speed question

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SUMMARY

The discussion centers on a ballistics test involving a 25.0 g bullet traveling at 1100 m/s that penetrates a 30.0 cm-thick target weighing 450 kg and exits at 900 m/s. The user attempts to calculate the time the bullet spends in the target using the equation t = d/v_avg, but arrives at an incorrect result. The average velocity was miscalculated, leading to confusion about the correct application of kinematic equations to determine the bullet's time in the target.

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In a ballistics test, a 25.0 g bullet traveling horizontally at 1100 m/s goes through a 30.0 cm-thick 450 kg stationary target and emerges with a speed of 900 m/s. The target is free to slide on a smooth horizontal surface.

How long is the bullet in the target?
i tried to use this equation : t = d/v_avg

900-1100 / 2 = -100 = vavg
.3=-100 t
t= .003
but it is saying that it is incorrect. can someone tell me what i am doing wrong?
 
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Using kinematic formula can you find the retardation produced in the block?
 
Last edited:
um i guess not then...
 

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