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**A car of mass 1200kg travelling at a velocity of 15m/s North collides head on with a small van of mass 2200kg travelling at 10m/s South. The vehicles stick together on impact and the collisions can be considered an isolated one. The contact time of the collision is 0.4 seconds.**

- Calc the velocity of thethe vehicles after the collision.
- Calc the average force of the van on the car.
- State average force of the car on the van.

- F=m*a
- F=(mass*Δvelocity)/Δtime
- momentum=mass*velocity
- ΔP=Pfinal-Pinital (note: p is momentum)
- Total P= m1v1 + m2v2

*The following calculations are correct now.*

- Total P= m1v1 + -(m2v2)
*car in opposite direction*

∴(2200*10)-(1200*15)=4,000 Ns(Newton secundum)

Since P=mv ∴v=P/m ∴ 4,000 / (1200+2200) = 1.17 m/s - Q2

Since F=m*a ∴ F=2200*a

where a = (v-u)/t ∴ (1.176-10)/0.4 = -22.06 m/s^2

thus F=2200*-22.06 = -48,529.4 Newtons - Same as q2, 48529.4 Newtons but in opposite direction, hence the +/- sign.

Proof:

F=1200*a

where a = (v-u)/t ∴ (1.176-(-15))/0.4 = 40.4412 m/s^2

thus F=1200*40.4412 = 48529.4 Newtons

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