Momentum Investigation: Car collision

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SUMMARY

The discussion centers on a collision analysis involving a Ford car (mass 1138 kg) and a stationary Vauxhall car (mass 1849 kg) that is pushed forward 13.42 m after the collision. The key question is whether the Ford was traveling over 13.41 m/s before the collision. Participants emphasize using the law of conservation of momentum, represented by the equation m1v1 + m2v2 = m1v3 + m2v4, to determine the post-collision velocity of the Vauxhall. However, they note that calculating the distance requires additional information, such as the frictional coefficient or time, indicating that the problem may lack sufficient data.

PREREQUISITES
  • Understanding of the law of conservation of momentum
  • Basic knowledge of physics concepts related to collisions
  • Familiarity with mass and velocity calculations
  • Knowledge of frictional forces and their impact on motion
NEXT STEPS
  • Research the law of conservation of momentum in elastic and inelastic collisions
  • Learn how to calculate frictional forces and coefficients in vehicle dynamics
  • Explore kinematic equations for motion to relate distance, velocity, and time
  • Investigate real-world applications of collision analysis in accident reconstruction
USEFUL FOR

This discussion is beneficial for physics students, automotive engineers, and accident reconstruction specialists seeking to understand the dynamics of vehicle collisions and the application of momentum principles.

Silurias
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(Q) A Ford car of mass 1138kg, collides with a Vauxhall car, of mass 1849kg, stationary at a stop line. The ford stops immediately but pushes the Vauxhall forward 13.42m. Was the Ford traveling over 13.41m/s before the collision?


I can't seem to find a solution as everything I have tried, I always end up needing a time value.
 
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Merely use the law of conservation of momentum. m1v1 + m2v2 = m1v3 + m2v4...
 
You can get the velocity of Vauxhall car by conservation of momentum but as for distance covered you either need the value of frictional coefficient between the car and road (and hence find the distance covered when it stops) or the time at which distance is measured. Are you sure the question is complete? Or it may be that 13.42 is the velocity and not the displacement?
 

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