Momentum Problem -- Bullet fired into a block of wood

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To determine how high the block rises after the bullet embeds itself, the problem can be divided into two stages: the impact and the subsequent rise. First, apply the conservation of momentum during the impact, where the initial momentum of the bullet equals the combined momentum of the bullet and block immediately after the collision. Next, use the conservation of energy to find the maximum height reached by the block and bullet together, converting kinetic energy into gravitational potential energy. The relevant equations include momentum conservation (m_bullet * v_bullet = (m_bullet + m_block) * v_final) and energy conservation (1/2 * m_total * v_final^2 = m_total * g * h). This approach will yield the height the block rises after the bullet's impact.
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Homework Statement
A gun is fired vertically into a block of wood(unknown mass) at rest directly above it. If the bullet has a mass of 24.0g and a speed of 310 m/s, how high will the block rise into the air after the bullet becomes embedded in it?
Relevant Equations
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A gun is fired vertically into a block of wood(unknown mass) at rest directly above it. If the bullet has a mass of 24.0g and a speed of 310 m/s, how high will the block rise into the air after the bullet becomes embedded in it?
 
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You need to make an effort to solve this yourself.
 
Break it into two stages, first the impact, then the subsequent rise of the block+bullet.
For "relevant equations ", what conservation laws might apply in each?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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