Momentum Problem: Final Momenta, Kinetic Energies Compared

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Homework Help Overview

The problem involves two carts on a track, where one cart has a spring-loaded piston that pushes against a passive cart with double the mass. The discussion centers around comparing the final momenta and kinetic energies of the two carts after the piston is released.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the conservation of momentum and question how the final momenta and kinetic energies of the carts relate to each other. There are attempts to clarify the implications of mass and velocity on momentum and kinetic energy.

Discussion Status

Some participants are exploring the implications of momentum conservation, while others are questioning the relationship between the kinetic energies of the carts. Hints have been offered to guide the discussion without providing direct answers.

Contextual Notes

Participants are navigating assumptions about the system, including the effects of the spring mechanism and the initial conditions of the carts. There is a focus on the lack of external forces and the implications for momentum and energy calculations.

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Homework Statement


Two carts are put back-to back on a track. Cart A has a spring-loaded piston; cart B, which has twice the inertial mass of cart A, is entirely passive. When the piston is released, it pushes against cart B, and the carts move apart. How do the magnitudes of the final momenta p and the kinetic energies K compare?

Please tell me if my approach is correct, because I'm not very clear on momentum:
Well if the piston is pushing against Cart B, then its momentum would be bigger than Cart A because it has both a greater velocity and a greater mass and momentum= velocity * mass. The kinetic energies- wouldn't the KE of cart A be bigger because it has more PE?
 
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Maiia said:
Please tell me if my approach is correct, because I'm not very clear on momentum:

Hi Maiia! :smile:

If there are no external forces, then momentum is always conserved.
 
that means that momentum inital = momentum final and since momentum inital is zero than momentum final is zero which means that final momentum for both is zero?
hmm but if i use KE= 1/2mv^2 then the KE of cart B would be bigger...?
 
Maiia said:
that means that momentum inital = momentum final and since momentum inital is zero than momentum final is zero which means that final momentum for both is zero?

Yes … the total momentum is zero, so one velocity will be twice the other (which one? :wink:)
hmm but if i use KE= 1/2mv^2 then the KE of cart B would be bigger...?

Hint: KE = momentum times what? :smile:
 

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