Monkey Climbing Rope: Solving for the Least Time to Reach a Banana at 6.90m

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SUMMARY

The discussion focuses on calculating the least time for a 12.0 kg monkey to climb a rope to reach a banana at a height of 6.90 meters without exceeding the rope's tension limit of 132 N. Using Newton's second law (F=ma), the acceleration was determined to be 11 m/s². The time taken to reach the banana was calculated using the kinematic equation, resulting in a time of approximately 1.12 seconds. The original poster confirmed the solution was correct after initial doubts.

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Homework Statement



A 12.0 kg monkey starts to climb a long rope to reach a banana located at a height of 6.90 m. The rope will snap if the tension exceeds 132 N. Calculate the least amount of time the monkey could take to reach the banana without breaking the rope.

Homework Equations



F=ma
x=xo +volt +1/2 at2

The Attempt at a Solution



I know that F=ma, therefore 132=12a
a=11m/s2

Then,
6.90 = 0 + 1/2 (11)t2
t2 = 1.25
t=1.12s

Something must be wrong, please help
 
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nevermind, i solved it!
 

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