More projectile motion problems (sigh)

Click For Summary
SUMMARY

This discussion focuses on solving two projectile motion problems involving a missile and a projectile fired from a cliff. The first problem requires calculating the launch angle and time to hit a target 1,200 miles away with a launch velocity of 15,000 ft/s. The second problem involves a projectile launched at a 30-degree angle from a 600 ft high cliff with an initial speed of 2,000 ft/s, requiring the horizontal distance traveled before hitting the ground. Key assumptions include neglecting air resistance and using Earth's gravity for calculations.

PREREQUISITES
  • Understanding of projectile motion equations
  • Knowledge of trigonometric functions (sine and cosine)
  • Familiarity with kinematic equations for horizontal and vertical motion
  • Basic algebra for solving equations with two unknowns
NEXT STEPS
  • Study the derivation of projectile motion equations
  • Learn how to apply kinematic equations in two dimensions
  • Explore the effects of air resistance on projectile motion
  • Practice solving real-world projectile motion problems using different angles and velocities
USEFUL FOR

Students in physics, educators teaching projectile motion concepts, and anyone interested in applying mathematical principles to real-world motion problems.

raizen91
Messages
14
Reaction score
2
got two more problems, hope you could help. more projectile problems...(sigh), i don't know how to start, hoping you guys could help me with the initial steps...


1. a missile is fired with a launch velocity of 15,000 ft/s at a target 1,200 miles away. at what angle must it be fired to hit the target? how long after it is fired will the target be hit.


2. a projectile is fired at an angle of 30 degrees above the horizontal from the top of a cliff 600 ft. high : the initial speed of the projectile is 2000 ft/s. how far will the projectile move horizontally before it hits level grained at the base of the cliff?
 
  • Like
Likes   Reactions: Alberto16
Physics news on Phys.org
i'd start with assumptions:
1) no air resistance
2) gravity is that of Earth
3) can you write an equation that describes the motion of the projectile that can be solved for the unknown you're looking for?

um... and the first one is worded poorly. "missiles" are usually "fired" or launched, but then they continue to burn their own fuel and propel themselves toward their targets :) thus, for question 1), the answer could well be "zero degrees" of launch angle, with the assumption that the thing's got wings and a guidance control system. :)))) but not likely.
better to assume it's "fired" like a projectile, much as in problem #2, with an initial velocity with horizontal and vertical components, and go from there.
 
raizen91 said:
got two more problems, hope you could help. more projectile problems...(sigh), i don't know how to start, hoping you guys could help me with the initial steps...


1. a missile is fired with a launch velocity of 15,000 ft/s at a target 1,200 miles away. at what angle must it be fired to hit the target? how long after it is fired will the target be hit.


2. a projectile is fired at an angle of 30 degrees above the horizontal from the top of a cliff 600 ft. high : the initial speed of the projectile is 2000 ft/s. how far will the projectile move horizontally before it hits level grained at the base of the cliff?

For 1 you might find this thread useful: https://www.physicsforums.com/showthread.php?t=112308

-Dan
 
plusaf said:
i'd start with assumptions:
1) no air resistance
2) gravity is that of Earth
3) can you write an equation that describes the motion of the projectile that can be solved for the unknown you're looking for?

um... and the first one is worded poorly. "missiles" are usually "fired" or launched, but then they continue to burn their own fuel and propel themselves toward their targets :) thus, for question 1), the answer could well be "zero degrees" of launch angle, with the assumption that the thing's got wings and a guidance control system. :)))) but not likely.
better to assume it's "fired" like a projectile, much as in problem #2, with an initial velocity with horizontal and vertical components, and go from there.
ok, here's what i did.
vx = r / t
dx/ v[subx] = vx * t / vx
= 1931,216.66 m / 4572.009
= 422.4 seconds
now for the angle
cos[theta] = vx / vx
= 4572.009 / 4572.009 =1
= 60 degrees
ok...is this right?
 
Not clear to me what you are doing here. Start by expressing the horizontal and vertical components of the initial velocity in terms of the initial speed (which is given) and the unknown angle. (Do this algebraically; don't plug in numbers until the last step.) Then:

(1) Write an expression for horizontal distance as a function of time. (Use x = x_0 + v_0 t[/tex].)<br /> <br /> (2) Write an expression relating the initial <i>vertical </i>speed with the total time of flight. (Use v = v_0 + a t.)<br /> <br /> You&#039;ll get two equations and two unknowns; you&#039;ll be able to solve for the angle and the time. When you finally plug in numbers, be sure to use proper units. (Convert distances to feet.)
 
silly wording but ithink its clear...i doubt they r referring to some sort of ..projectile mathematics...use equations of motion...sumbody do it...my hands r lazy..ok ..good luck..
 
Click the Basic Motion tutorial in my signature for some help with methodology.
 
Let's walkthrough real quickly.

1. a missile is fired with a launch velocity of 15,000 ft/s at a target 1,200 miles away. at what angle must it be fired to hit the target? how long after it is fired will the target be hit.

The velocity must be split up into two components. X and Y. Cos@ and Sin@ respectively.

Vix=15000cos@
X=1200 miles (6336000 feet)
Since there is no acceleration horizontally, the equation is X=Vix*t.

Viy=15000sin@
Y=maximum height which occurs halfway (600 miles) at t/2.
Since there is acceleration vertically downward, the equation is:
Y=Viy*t+1/2*g(t^2)

Note that this equation for the Y direction is a parabolic equation and has two zeros. Initial point and the point where it hits.



2. a projectile is fired at an angle of 30 degrees above the horizontal from the top of a cliff 600 ft. high : the initial speed of the projectile is 2000 ft/s. how far will the projectile move horizontally before it hits level grained at the base of the cliff?

This is an easier problem than number one.

@=30 degrees.
Vi=2000 ft/s
Vix=2000cos30
Viy=2000sin30
X=?
Y=600 ft

Y=Viy*t + 1/2*g*t^2
X=Vix*t

Find the total time it takes for it to hit the ground (hint, use the equation for the Y direction and then plug in t for the equation for X direction)
 
For qn 1, what you could actually do was to solve the question using the eqns for both the horizontal and vertical components. Assume no air resistance, ur horizontal component eqn will be simply s=ut while the eqn for vertical component will be s=ut+1/2at^2.. Find t in terms of s and u using the the first eqn and sub the t into ur 2nd eqn..and thus, simply solve for
the unknown angle..

Pls note that that ur vertical speed must also be expressed in the (sin) or (cos) of the unknown angle.
 
Last edited:

Similar threads

  • · Replies 3 ·
Replies
3
Views
859
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
4
Views
2K
Replies
15
Views
3K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K