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SUMMARY

The discussion focuses on the calculation of kinetic energy ratios when an object bounces off a wall and when a ball drops, gaining kinetic energy. When an object hits a wall and bounces back with half its original speed, the ratio of final kinetic energy to initial kinetic energy is determined to be 1:2. Additionally, when considering air resistance, the gravitational potential energy lost by a ball that gains 30 J of kinetic energy is acknowledged to be greater than 30 J due to energy loss from air resistance.

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  • Basic principles of momentum and energy conservation
  • Knowledge of gravitational potential energy concepts
  • Familiarity with the effects of air resistance on falling objects
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future_vet
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An object hits a wall and bounces back with half if its original speed. What is the ratio of the final kinetic energy to the initial kinetic energy?
I am not sure I understand the question, is it 1:2?

A ball drops some distance and gains 30 J of kinetic energy. Do not ignore air resistance. How much gravitational potential did the ball lose?
I would say more than 30J since we have to take air resistance into consideration.

Thanks!
 
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future_vet said:
An object hits a wall and bounces back with half if its original speed. What is the ratio of the final kinetic energy to the initial kinetic energy?
I am not sure I understand the question, is it 1:2?

Not so fast. Write down the kinetic energies and look at the ratio.
 
First is 1 and second is 0.5 => 1/0.5 =2. Is this correct?
 
future_vet said:
First is 1 and second is 0.5 => 1/0.5 =2. Is this correct?

No, it isn't. The first kinetic energy is 1/2 m v^2, and the second is 1/2 m (1/2 v)^2. What is their ratio?
 
future_vet said:
First is 1 and second is 0.5 => 1/0.5 =2. Is this correct?

No - the kinetic energy of the object is (1/2)mv^2.
 
I am not sure I get it, but it looks like 1:0.5 to me...
 
future_vet said:
I am not sure I get it, but it looks like 1:0.5 to me...


Do you know how to take the ratio of 1/2 m (1/2 v)^2 (final kinetic energy) and 1/2 m v^2 (initial kinetic energy)?
 
I guess not... It's ok, I'll figure it out.

Thanks!
 

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