MOSFET Without Rs (source resistance) Help

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SUMMARY

The discussion centers on biasing the IRF510 MOSFET without a source resistor (Rs) and the challenges faced in achieving the desired output voltage. The user attempted to set a bias voltage of 4.5V using a voltage divider with R1 and R2 both at 100K, with a supply voltage (Vdd) of 9V and a drain resistor (Rd) of 600 ohms. Despite calculations suggesting an output of 3V, the actual output was significantly lower, around 300mV, indicating that the absence of Rs negatively impacts the circuit's performance. The conversation highlights the necessity of including Rs for achieving the expected output voltage in practical applications.

PREREQUISITES
  • Understanding of MOSFET operation, specifically the IRF510 model.
  • Knowledge of voltage divider circuits and biasing techniques.
  • Familiarity with Ohm's Law and basic circuit analysis.
  • Experience with practical circuit assembly and troubleshooting.
NEXT STEPS
  • Research the impact of source resistors on MOSFET biasing and performance.
  • Learn about the characteristics and parameters of the IRF510 MOSFET.
  • Explore voltage divider design principles for biasing transistors.
  • Investigate common source amplifier configurations and their applications.
USEFUL FOR

Electronics engineers, hobbyists working with MOSFETs, and anyone involved in designing or troubleshooting amplifier circuits will benefit from this discussion.

vco.asm
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I'm encounter a problem in biasing mosfet irf510 ;
please someone answer me... why i can not get an output over than 3V

i had using voltage divider to bias at 4.5V (R1=R2=100K) ; Vdd=9V; Vout should be = 3V .. Rd=600 OHM where Id=10mA the problem here that i do not like to use Rs as source resistor . the worset of result is not as i calc ...pleeez some one tell me why can not get an out put equal to 3V .. why Id not as i determinted ?

best regard;
MR,10GHz
it should be mentained here that when you put Rs ; you will get what you want; and my colpitts oscillator then work in Common Source; when you remove Rs and recalc the circuit its faild

Kn=124 mA/V2 @ gfs =1.3@3.4A
iD=kn (Vgs-Vgs(th))^2
 
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I'm not sure I understand your question. I think you're saying you have a Vdd or 9V, an Rd of 600 ohms and an Id of 10 mA. The 600 ohms with 10 mA with give you a voltage drop of 6V and 9V - 6V = 3V.

If you want more than 3V at the drain you could either lower your bias voltage or the value of Rd.
 
yes that's right but in practical in my lab when i build the circuit it's did not success why?

Code:
9V
|-------------|
|                   Rd=660
R1=100K        |-----------------V0 = should be >5 put in practical about 300mv Why?
|                --
|-----------| IRF510
|                --
R2=100k         |
|                   |
|                   |
---------------
       ---
         -
--
-
 
Last edited by a moderator:

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