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Motion described with differential equation

  1. May 6, 2014 #1
    1. http://i.imgur.com/3xya7IM.jpg




    3. I curently do not understand how to jump to finding an acceleration due to gravity (in those terms asked) from the differential equations
     
  2. jcsd
  3. May 6, 2014 #2

    ChrisVer

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    Gold Member

    From the up eq, you can find its time (depending on g)... and for the down, you can do the same...
    then you can solve for g since you know their summation...
     
  4. May 6, 2014 #3

    HallsofIvy

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    Staff Emeritus
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    From [itex]dv/dt= -mg- kv[/itex] you can get
    [tex]\frac{dv}{mg+ kv}= -dt[/tex]
    Integrate both sides.
     
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