Motion Homework -- A particle moving along the x-axis....

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SUMMARY

The position function of a particle moving along the x-axis is defined as x(t) = 6.00 - 7.00t². To determine when the particle momentarily stops, the velocity function v(t) must be calculated and set to zero. The equation for the position at the origin is solved as 0 = 6 - 7t², yielding two time values: one positive and one negative. The correct interpretation of the variables and clear delineation of problem parts are essential for accurate solutions.

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fahadff
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Homework Statement


The position function x(t) of a particle moving along an x axis is x = 6.00 - 7.00t2, with x in meters and t in seconds.

Homework Equations


(a)[/B] At what time and
(b) where does the particle (momentarily) stop? At what
(c) negative time and
(d) positive time does the particle pass through the origin?

The Attempt at a Solution


0= 6.00-7.00x^2
x=0.925
 
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fahadff said:

Homework Statement


The position function x(t) of a particle moving along an x axis is x = 6.00 - 7.00t2, with x in meters and t in seconds.

Homework Equations


(a)[/B] At what time and
(b) where does the particle (momentarily) stop? At what
(c) negative time and
(d) positive time does the particle pass through the origin?

The Attempt at a Solution


0= 6.00-7.00x^2
x=0.925
You have mixed up your variables. The equation is ##x = 6 - 7t^2##, so when the position x is 0, the equation becomes ##0 = 6 - 7t^2##. When you solve this equation, you get two values of t. One of them is positive and one is negative. These will be the answers to parts c and d.

For parts a and b, you need to calculate the velocity, v(t), and determine at what time(s) it is zero.
 
You should also state clearly, which part of the problem you are trying to solve with each set of equations you present in your work.
 

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