Motion in Space: Velocity and Acceleration

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The discussion focuses on the motion of two objects, A and B, represented by parametric equations tracing circular paths. Object A moves at a standard rate, while object B moves faster due to its equation involving a higher frequency. The participants calculate the velocity and acceleration for both objects, noting that while their tangential components are equal, object B has a larger normal component, indicating quicker direction changes. There is a correction needed in the definitions of velocity and acceleration, which prompts further clarification from other participants. Overall, the thread emphasizes the importance of accurately defining motion concepts in multivariable calculus.
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Homework Statement


The position function of objects A and B describe different motion along the same path for t >= 0.
A: r(t) = cos(t)i + sin(t)j
B: r(t) = cos(3t)i + sin(3t)j
a) Sketch the path followed by A and B
b) Find the velocity and acceleration of A and B and discuss the distance
c) Express the acceleration of A and B in terms of the tangential and normal components and discuss the difference

Homework Equations


T(t) = velocity/speed (unit tangent vector)
N(t) = T'(t)/ absolute value of T'(t) (unit normal vector)
a_T = v'
a_N = kv^{2}
a = v'T + kV^{2}N (k is curvature)

The Attempt at a Solution


Ok, this was a problem for my multivariable calculus class but if the mods feel that it belongs in a physics subforum then by all means move it there :).
a) I know that both functions are circles with radius r = 1, traced out in a counterclockwise direction
b) v(t)_A = \int r(t) dt = -sin(t)i + cos(t)j
v(t)_B = \int r(t) dt = -3sin(3t)i + 3cos(3t)j
a(t)_A = \int v(t) dt = -cos(t)i - sin(t)j
a(t)_B = \int v(t) dt = -9cos(3t)i - 9sin(3t)j
The difference between the two is that the 'B' function is traced out much faster than the 'A' function
c) For A:
T(t) = -sin(t)i + cos(t)j
N(t) = -cos(t)i - sin(t)j
The magnitude of T, N is equal to 1, as is the curvature k
Tangential acceleration is:
a_T = -cos(t)i - sin(t)j
Normal acceleration is:
a_N = sin^2(t)i + cos^2(t)j
For B:
T(t) = -sin(3t)i + cos(3t)j
N(t) = -cos(3t)i - sin(3t)j
The magnitude of T, N is equal to 3 and the curvature k is equal to 1
a_T = -9cos(3t)i - 9sin(3t)j
a_N = 9sin^2(3t)i + 9cos^2(3t)j
The tangential component shows the rate of change of velocity and the normal component shows the rate of change of direction. In this case the tangential components of the two functions are equal. However B has a larger normal component, therefore it changes direction more quickly. This problem was worth 20 points; however, I only received 16... I am allowed to make a correction for full credit so I was hoping somebody could tell me where I went wrong :)
 
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What's the definition of velocity, in terms of position? What's the definition of acceleration, in terms of velocity?

What you wrote for the answers to the velocity and acceleration are OK, but the definitions you used are incorrect.
 
SteamKing said:
What's the definition of velocity, in terms of position? What's the definition of acceleration, in terms of velocity?

What you wrote for the answers to the velocity and acceleration are OK, but the definitions you used are incorrect.
Thank you for pointing that out, I'll make the changes in a moment...know that when I was finding velocity and accel I did differentiate. I did not integrate
 
I can't seem to edit my original post, perhaps the mods would be so kind as to change my mistake :)
 
SteamKing said:
What's the definition of velocity, in terms of position? What's the definition of acceleration, in terms of velocity?

What you wrote for the answers to the velocity and acceleration are OK, but the definitions you used are incorrect.
Also, besides the definition mistake was there anything else you noticed that was wrong? I have double checked but I believe that I answered everything correctly
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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