Motion in Two or Three Dimension : Projectile motion

Click For Summary

Homework Help Overview

The discussion revolves around a projectile motion problem involving a projectile launched at a 60° angle above the horizontal. Participants are examining the change in velocity from launch to just before landing, specifically focusing on the initial and final velocities of the projectile.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to relate the initial and final velocities using kinematic equations. There are questions regarding the correct interpretation of the change in velocity and the values of vertical displacement (Yf - Yo).

Discussion Status

Some participants have offered algebraic relationships and questioned the accuracy of the problem statement. There is an ongoing exploration of the implications of the projectile being launched and landing on the same level ground, but no consensus has been reached on the correct approach or values.

Contextual Notes

Participants note uncertainty regarding the vertical displacement (Yf - Yo) and whether the problem statement was accurately conveyed. There are indications of potential flaws in the problem setup that may affect the analysis.

physicos
Messages
46
Reaction score
1

Homework Statement



A projectile is launched at a 60° angle above the horizontal on level ground. The change in its velocity between launch and just before landing is found to be Δv = vlanding _ vlaunch = -20 y^ m/s .
What is the initial velocity of the Projectile ?
What is its final velocity just before landing ?

Homework Equations



Δv = vlanding _ vlaunch = -20 y^
m/s .
3.The attempt at a solution
I considered :
Vox - Vfx = 0 and Voy - Vfy = -20
knowing that V²fy - V²oy= -2g (Yf-Yo) But I couldn't go further

Homework Statement


Homework Equations


The Attempt at a Solution

 
Last edited:
Physics news on Phys.org
physicos said:
Vox + Vfx = 0 and Voy + Vfy = -20
"+"?
knowing that V²fy - V²oy= -2g (Yf-Yo)

What is the value of Yf-Yo?
 
Yes , just saw it ! I edited the post !
I have no idea about Yf-Yo ,I couldn't guess it from the problem statement !
 
physicos said:
Yes , just saw it ! I edited the post !
I have no idea about Yf-Yo ,I couldn't guess it from the problem statement !
It is launched from, and lands on, the same level ground.
 
so V landing = 0 ?? Because we know that v = sqrt(Vo²-2g(Y-Yo))
 
physicos said:
so V landing = 0 ?? Because we know that v = sqrt(Vo²-2g(Y-Yo))
No, you should check your algebra on that equation. But regardless, there are serious flaws in the problem statement. Did you word it correctly?
 

Similar threads

Replies
40
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
8
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 15 ·
Replies
15
Views
27K
  • · Replies 15 ·
Replies
15
Views
2K