Motion of an Object: Displacement & Average Velocity

AI Thread Summary
An object accelerates from rest at 3.0 m/s² for 4.0 seconds, reaching a velocity of 12.0 m/s. It maintains this constant velocity for 7.0 seconds, followed by a uniform deceleration that brings it to rest over 5.0 seconds. The displacements for each stage are calculated as 24 m during acceleration, 84 m at constant velocity, and 30 m during deceleration. The average velocity over the entire motion can be derived from the total displacement and total time. The discussion emphasizes using both algebraic methods and graphical representations for solving motion problems.
Stewkatt
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Homework Statement
I drew a time line and tried but i think I missed something can someone try this question and show the steps they took? Thank you!
Relevant Equations
Vav=(vf-vi)/2 or delta d/ delta t
a=(vf-vi)/t
An object starts from rest and accelerates at 3.0 m/s2 for 4.0 s. Its velocity remains constant for 7.0 s, and it finally comes to rest with uniform deceleration after another 5.0 s. Find the following:
a. the displacement for each stage of the motion
b. the average velocity over the whole time
interval.
 
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Let us break the question into bite size pieces. First:
An object starts from rest and accelerates at 3.0 m/s2 for 4.0 s.
What is its position at t=4.0s ?
What is its velocity at t= 4.0s ?
 
Hey, I figured it out. Here is my work.
image.jpg
 
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That's looks correct. Note that you could also have drawn a velocity against time graph and calculated the displacements as the area under each section of the graph.
 
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PeroK said:
That's looks correct. Note that you could also have drawn a velocity against time graph and calculated the displacements as the area under each section of the graph.
Hey, my teacher prefers I solve things with algebra with a timeline, but I’ll keep that in mind
 
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Stewkatt said:
Hey, my teacher prefers I solve things with algebra with a timeline, but I’ll keep that in mind
Both is best (particularly while you are learning) !
 
Stewkatt said:
Hey, I figured it out. Here is my work. View attachment 296860
You can make your working a bit shorter.

Stage 2 is at constant velocity (12.0m/s) so using ½(12m/s+12m/s)*7.0s seems a bit excessive.
d₂ = 12.0m/s*7.0s should be acceptable.

For Stage 3. there’s no need to find and use acceleration; just multiply average velocity by time:
##d = \frac {(v_i+v_f)} {2}t##.
 
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The quickest way is to note that the maximum speed (during the middle phase) is ##12m/s## and the average speed during both the acceleration and deceleration phases is half of this. So, the displacements are: ##d_1 = 4s \times 6m/s = 24m##, ##d_2 = 7s \times 12m/s = 84m##, ##d_3 = 5s \times 6m/s = 30m##.
 
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Thank you for all your help everyone :)
 
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