Motion Problem: Race Car's Position & Instantaneous Velocity at t = 3.5 s

  • Thread starter Thread starter Rymac
  • Start date Start date
  • Tags Tags
    Motion
Click For Summary
SUMMARY

The discussion focuses on calculating the instantaneous velocity of a race car at t = 3.5 seconds, given its position function x = (5.0 m/s)t + (0.80 m/s³)t³. Participants are tasked with determining this velocity using varying time intervals of 0.40 s, 0.20 s, and 0.10 s. The average velocity over the first 3.5 seconds is noted as 14.8 m/s, prompting a comparison with the instantaneous velocity results. Understanding the definitions of average and instantaneous velocity is crucial for solving the problem accurately.

PREREQUISITES
  • Understanding of calculus concepts, specifically derivatives
  • Familiarity with kinematic equations
  • Ability to plot graphs of functions
  • Knowledge of average vs. instantaneous velocity
NEXT STEPS
  • Learn how to calculate derivatives to find instantaneous velocity
  • Explore graphing techniques for position vs. time functions
  • Study the relationship between average and instantaneous velocity in physics
  • Practice problems involving polynomial motion equations
USEFUL FOR

Students in physics courses, particularly those studying kinematics, as well as educators looking to enhance their teaching methods on motion concepts.

Rymac
Messages
1
Reaction score
0
This problem seems simple enough, I guess I just don't really understand what it's looking for in the (b) portion.
A race car moves such that its position fits the relationship where x is measured in meters and t in seconds.
x = (5.0 m/s)t + (0.80 m/s³)t³

(a) Plot a graph of the car's position versus time. (Do this on paper. Your instructor may ask you to turn in this work.)

(b) Determine the instantaneous velocity of the car at t = 3.5 s, using time intervals of 0.40 s, 0.20 s, and 0.10 s.

Δt = 0.40 s ____________m/s

Δt = 0.20 s ____________m/s

Δt = 0.10 s ____________m/s


(c) Compare the average velocity during the first 3.5 s with the results of (d).
The average velocity of _14.8_ m/s is (*d1*) much less than (d2) about the same as (d3) much greater than the instantaneous velocity.
 
Physics news on Phys.org
You need to show that you have but some kind of thought into this problem.

what is your definition of Average and instanenous velocity?
 

Similar threads

  • · Replies 23 ·
Replies
23
Views
5K
  • · Replies 5 ·
Replies
5
Views
8K
  • · Replies 15 ·
Replies
15
Views
3K
Replies
12
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K
Replies
6
Views
7K
  • · Replies 6 ·
Replies
6
Views
7K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 10 ·
Replies
10
Views
13K