Motion Problem: Struggling with Angle w.r.t Wall

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Garen
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Motion Problem!

Homework Statement



Diagram of a particle moving between two parallel walls 18.4 m apart, starting at the left wall with a dotted curved path to the right wall; labels show 5.5 m/s horizontal velocity, 0.96 m/s² acceleration parallel to the walls, and the 18.4 m separation.


The Attempt at a Solution



Okay, so I got number one (6.36904) but I'm having real trouble getting the angle w.r.t the wall. At first I thought of taking the t (from
Equation: Δx = v_x0 t, written as plain text with the displacement delta x equal to initial horizontal velocity v_x0 multiplied by time t.
)[/URL] then multiplying it by the acceleration to get the y component of the velocity. I then thought of taking the inverse tangent of (5.5/Vy). But I am not sure if it is right. Did I do something wrong?
 
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Yes, you do want something like tan(angle) = vx / vy. This gives you the angle between your vector and the vertical direction (the wall is vertical).
 


You need the x and y components of the velocity and then you can use your tangent method.
 


Kurdt said:
You need the x and y components of the velocity and then you can use your tangent method.

That's what I was trying to do, but is my method of getting the y component of the velocity (listed above) right? Or was I supposed to use another method?
 


You'll have to use some kinematic equations. You need to find the time it takes to hit the wall and then the speed it will be traveling in the vertical direction due to that acceleration after that time. If you got the first part correct then you should already know both components surely?