Movement of a Body on horizontal surface

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Homework Help Overview

The problem involves a body moving on a horizontal surface under the influence of a horizontal force that is 60% of its weight. The task is to determine the total time of movement after the body has traveled a distance of 24 meters.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the nature of the horizontal force, questioning whether it is the tractive force or the resultant of tractive and frictional forces. There are attempts to derive acceleration and velocity, with some participants checking algebraic calculations and discussing the implications of the problem's wording.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and questioning the completeness of the information provided. Some have suggested that the total movement may consist of phases of acceleration and constant velocity, while others note the absence of friction in the problem statement.

Contextual Notes

There is uncertainty regarding the initial velocity of the body and the role of friction, as it is not mentioned in the problem statement. Additionally, the original poster's calculations have led to varying estimates of the total time of movement, which contrasts with a provided answer from a textbook.

inv4lid
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Homework Statement


A body that is on a horizontal surface begins to move under the action of horizontal force equal to 60% of its weight. Force acts for a while, then stops acting. Determine the total time of movement if the body has traveled a distance of 24m.

Homework Equations


gd1krNzHSbuPIJChPyJTWg.png
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I'm not really sure about the "horizontal force". Is it the tractive force or is it the resultant of the difference between the tractive and friction one?
I tried like both(but i really assume the horizontal is the resultant force) and from there we can probably get the acceleration.

The Attempt at a Solution


R = Ft - Ff = ma;
60% = 0,6;
where g is 10N/kg
0,6 m*g = ma;
6m = ma;
a = 6 (m/s2);

I've tried using that formula:
v12 - v02 = 2as
v1 - v0 = √(2as)
We don't know though any of speeds.
s = (v0 + v1)t/2
from there:
48 = (v0 + v1)t
S = v0t + a/2 * t2
24 = v0t + 3t2
tried more things but all attempts led to nothing.

Any help would be appreciated, thanks!
 

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What was the velocity of the body before it “begins to move?”

Check your algebra on solving for the final velocity.
 
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Chestermiller said:
What was the velocity of the body before it “begins to move?”

Check your algebra on solving for the final velocity.
It was 0, yes, i know.
I got some answers between 1,7 and 2,8 seconds. By the way, the end of the book says the true answer is 6s
The problem also belongs to the category of "simple problems", so I think the solution shouldn't be so
difficult. Usually, the problems of this category are solved in 1-2 steps.
 
inv4lid said:
A body that is on a horizontal surface begins to move under the action of horizontal force equal to 60% of its weight. Force acts for a while, then stops acting. Determine the total time of movement if the body has traveled a distance of 24m.
The wording strongly suggests that the "total movement" is made up of a period of constant acceleration while the force is applied, plus a further period of constant velocity. An answer of 6 seconds would then be feasible, but if this is correct then there is insufficient information to deduce it.
Please check you have provided all the information in the question.
 
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Friction isn't mentioned in the problem statement.
 

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