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inv4lid
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Homework Statement
A body that is on a horizontal surface begins to move under the action of horizontal force equal to 60% of its weight. Force acts for a while, then stops acting. Determine the total time of movement if the body has traveled a distance of 24m.
Homework Equations
I'm not really sure about the "horizontal force". Is it the tractive force or is it the resultant of the difference between the tractive and friction one?
I tried like both(but i really assume the horizontal is the resultant force) and from there we can probably get the acceleration.
The Attempt at a Solution
R = Ft - Ff = ma;
60% = 0,6;
where g is 10N/kg
0,6 m*g = ma;
6m = ma;
a = 6 (m/s2);
I've tried using that formula:
v12 - v02 = 2as
v1 - v0 = √(2as)
We don't know though any of speeds.
s = (v0 + v1)t/2
from there:
48 = (v0 + v1)t
S = v0t + a/2 * t2
24 = v0t + 3t2
tried more things but all attempts led to nothing.
Any help would be appreciated, thanks!
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