Movement with sine acceleration

yaqwsx
Messages
2
Reaction score
0
Hello,
first of all, excuse my English. I have no experience witch describing mathematics problems in English.
I have a movement with sine acceleration. I need to get equation of velocity depending on track (I am not sure if that's the right expression in English - on the traveled distance).
Here's my equation for acceleration: a = A * sin(∏*t/T)
2011_11_02_21_12_39_000000_image001_png.png

where a is acceleration, A is the maximal acceleration, t is actual time and T is the whole time of accelerating. I want to get a velocity, so I integrated this expression and added parameter c to satisfy the condition: when t = 0, v = 0. I got this equation: v = (A*T/∏)*(1-cos(pi*t/T))
2011_11_02_21_13_12_000000_image003_png.png

If I wanted dependency veleocity on time, this would be enought, but I wanted depency velocity on track, so I have integrated... s = A*T*(∏*t - T*sin(∏*t/T))/∏^2
2011_11_02_21_13_27_000000_image005_png.png

I wanted to express t from this equation and put it into expression for velocity. For that I need to solve an equation in form a*x +sin(b*x) = c, which I can't solve. And as I have read it isn't something easy...
How can I get dependency of velocity on track for this movenent? I think there has to be a simple solution, but I don't see it. Can you help me, please?
 
Physics news on Phys.org
can you just simply isolate AT from the equation for s and replace AT with it in the equation for v?
 
I think isolating AT won't help me - T is the whole time of accelerating - it's a constant. A is also a constnt. I need get rid of t - which is a variable and create dependency with s.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
3K
  • · Replies 8 ·
Replies
8
Views
6K
  • · Replies 5 ·
Replies
5
Views
5K