Moving cart that rotates when acclerating

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SUMMARY

The discussion focuses on calculating the linear acceleration required for a cart to tip over, given specific forces acting on it. The forces include vertical reaction forces R1 and R2 on the rear and front wheels, friction forces F1 and F2, and the gravitational force Mg acting at the center of gravity. The tipping occurs when R1 equals zero, leading to a rotation about R2. The equations of motion and moments are established, but the user seeks a solution without numerical values for F1, F2, or Mg.

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  • Knowledge of static equilibrium and moments
  • Familiarity with forces acting on rigid bodies
  • Basic concepts of angular acceleration and moment of inertia
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Homework Statement


There are 5 forces R1 and R2 which are the vertical reaction forces on the rear and front wheels respectively. F1 and F2 are the friction forces on the wheels. And finally Mg which acts at the center of gravity which is closer to R2 then R1. Only known value is R1 which will be 0 when tipping occurs, because of this the cart will rotate about R2. The rear wheels are powered by gears while the front ones are just stuck to an axel. I would like to know the linear acceleration that the cart must undergo in order for tipping to occur. I don't really want to plug in numbers just solve it leaving the variable terms


Homework Equations


Summ of the forces in the x,y and moments.


The Attempt at a Solution


forces in x =-f1-f2=ma.
forces in y=R1+R2-mg=0
moments about R1 where clockwise is positive=mg(d1)-R2(d2)=I*alpha(angular acceleration)
 
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d1 is the distance from R2 to cg and d2 is the distance from R1 to cg. I is the moment of inertia about the cg. I know R1=0 so I can get a value for R2 but that doesn't seem to help. I'm not sure how to solve the equation since I don't have a value for F1, F2 or Mg.
 

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