# Yet another statics problem involving several forces

mechanim

## Homework Statement

The body is connected to the ground with a moving joint at B, the body slides with no friction at A. ## Homework Equations

ΣF=0 => ΣFx=0 & ΣFy=0
ΣM=0

## The Attempt at a Solution At this point I started calculating:
ΣFx=>P-R2-F1, so: P=R2+F1
ΣFy=> R1+F2-mg=0, so: R1+F2=mg

I'm quite confused when it comes to the moment around B, I know that Moment=force*distance, but how do I draw all the distance that I need?

I thought about something like that: So, the distance between F1 and the point B is a, while the distance between F2 and B is b.
Knowing this, I assume that the moment would look like that:

Mb: P+mg-F2*b-F1*a-R2-R1=0
now I replace P and mg according to the previous equations:
Mb: R2+F1+R1+F2-F2*b-F1*a-R2-R1=0
now the weird part is that I could reduce almost everything in the equation above, so that I would only be left with:
Mb: b-a=0
but it doesn't make any sense.

I would appreciate any help, thank you in advance!

siddharth23
Two things:
1) the 'mg' force always acts from the center of mass of the object
2) how exactly does the body slide? Seems to be some mistake there

• mechanim
Homework Helper
Gold Member
2) how exactly does the body slide? Seems to be some mistake there

I don't think they are saying it slides. I think the point is that there is no friction at "a" so that it could slide if "b" wasn't there. If there was friction at "a" (or if "a" was another mounting like that at "b") then I think you would find it hard to calculate how forces are shared between "a" and "b".

• mechanim
Homework Helper
Gold Member
Deleted.

mechanim
It says exactly that the body slides at A with no friction. I don't know exactly what they mean by that either. What do you think about the equations though?