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Multiple dielectrics inserted in capacitor

  1. Mar 11, 2013 #1
    1. The problem statement, all variables and given/known data
    A parallel-plate capacitor is constructed by filling
    the space between two square plates with blocks of three
    dielectric materials, as in Figure P26.61. You may assume
    that l >> d. (a) Find an expression for the capacitance of
    the device in terms of the plate area A and d, κ1, κ2, and
    κ3. (b) Calculate the capacitance using the values
    A = 1.00 cm2, d = 2.00 mm, κ1 = 4.90, κ2 = 5.60, and
    κ3 = 2.10.


    2. Relevant equations



    3. The attempt at a solution

    I understand that κ1 is parallel to κ2 and κ3 and just make a circuit out of it. The problem I'm having is that it is saying the expression for the capacitance of κ1 is

    κ1ε(A/2)/d

    and for the capacitors of κ2 and κ3

    κ2ε(A/2)/(d/2) and κ3(A/2)/(d/2)

    However, my question is why for K2 and K3 isn't it Kε(A/4)/(d/2) since they only consist of one fourth the area of the whole capacitor
     

    Attached Files:

  2. jcsd
  3. Mar 11, 2013 #2

    NascentOxygen

    User Avatar

    Staff: Mentor

    K1 has half of the area of each square plate. The combination K2 with K3 can be viewed as a pair of capacitors in series.
     
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