Understanding the Role of the Dirac Delta Function in Multipolar Polarization

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The discussion focuses on the application of the Dirac Delta function in calculating the matrix elements of microscopic polarization between the 1s and 2s states of the hydrogen atom. The integral expression for polarization, P(r), incorporates the delta function, which effectively restricts the integration to the point where r' equals r. Participants clarify that the delta function simplifies the calculation by ensuring that contributions only come from this specific point, making the integrand zero elsewhere. The operator P(r) is understood as involving the product of the charge density, ρ(r), and the position vector, r. Overall, the Dirac Delta function plays a crucial role in isolating the relevant contributions in the integral.
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Homework Statement


Using the explicit expression for the mulitpolar polarization, find the matrix elements <2s | P(r) | 1s> of the microscopic polarization between the 1s and 2s states of the hydrogen atom.

Homework Equations


P(r) = \int dr&#039; r&#039; \rho(r&#039;) \delta(r-r&#039;)

I don't understand how the Dirac Delta Function is supposed work? What it is and how does it operate in the intergral?

The Attempt at a Solution


&lt;\psi(2s) | P(r) | \psi(1s) = \int dr&#039; r&#039; \rho(r&#039;) \delta(r-r&#039;)

\psi(1s), \psi(2s) are just H-atom wavefunctions.
 
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I'm not familiar with this operator, but just looking at the equation for P(r) I would read it as rho(r)*r. The delta function restricts the integrand to the point where r' = r, and it's equal to zero for other values of r'.
 
This is easy!
 

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