Multipole expansion for the case r'>>r and r>>r'

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SUMMARY

The discussion focuses on the multipole expansion in the context of two scenarios: when the distance r is much greater than r' (r >> r') and when r' is much greater than r (r' >> r). In the first case, the potential V(r) simplifies to V(r) = constant * 1/r * P0(cos a), where higher-order terms are negligible. In the second case, the potential is expressed as V(r) = constant * 1/r' * P0(cos a'), indicating that it becomes constant and independent of r when higher-order terms are neglected. The key takeaway is that the lowest order term that depends on r is crucial for determining the electric field.

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pallab
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Homework Statement
what is the multipole expansion of a charge q for two extreme cases r>>r' and r'>> r?
Relevant Equations
1/R=(1/r)* [ summation (r'/r)^nPn(cos a)]
for the case, r>>r' the higher-order term like 1/r^2 and above that is negligible.
so V(r)=cons.*1/r*P0(cos a)
but for the case r'>>r will it be V(r)=cons.*1/r'[ summation Pn(cos a')t'^n] where t'=r/r'
now if we neglect higher-order term of r/r' then V(r)=cons.*1/r'*P0(cos a') which is constant not a function of r.
is it correct? what is the physics behind it?
 
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You might want to keep the lowest order that does depend on r. That's what matters for the electric field.
 
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