Multivariable Analysis: Another Question Re: D&K Lemma 2.2.7

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SUMMARY

This discussion centers on the proof of continuity for the function ##\phi_a## as presented in Lemma 2.2.7 of "Multidimensional Real Analysis I: Differentiation" by J. J. Duistermaat and J. A. C. Kolk. The proof utilizes the relationship between the limit of the Euclidean norm of the error term ##\epsilon_a(h)## and the continuity of the mapping ##\phi_a## at point ##a##. Specifically, it demonstrates that as ##h## approaches zero, the limit of the ratio of the norms converges to zero, confirming that ##\phi_a## is continuous at ##a##.

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I am reading "Multidimensional Real Analysis I: Differentiation" by J. J. Duistermaat and J. A. C. Kolk ...

I am focused on Chapter 2: Differentiation ... ...

I need help with another aspect of the proof of Lemma 2.2.7 (Hadamard...) ... ...

Duistermaat and Kolk's Lemma 2.2.7 and its proof read as follows:
D&K - 1 -  Lemma 2.2.7 ... ... PART 1 ... .png

D&K - 2 -  Lemma 2.2.7 ... ... PART 2 ... .png


Near to the end of the above text D&K write the following:

" ... ... A direct computation gives ##\| \epsilon_a(h) h^t \|_{ Eucl } = \| \epsilon_a(h) \| \| h \|## , hence##\lim_{ h \rightarrow 0 } \frac{ \| \epsilon_a(h) h^t \|_{ Eucl } }{ \| h \|^2 } = \lim_{ h \rightarrow 0 } \frac{ \| \epsilon_a(h) \| }{ \| h \| } = 0## This shows that ##\phi_a## is continuous at ##a##. ... ... "

My questions are as follows:

Question 1

... how/why does the above show that ##\phi_a## is continuous at ##a##. ... ...?

Can someone please demonstrate explicitly, formally and rigorously that ##\phi_a## is continuous at ##a##. ... ...?Question 2

How/why does the proof of Hadamard's Lemma 2.2.7 imply that ##f## is continuous at ##a## if ##f## is differentiable at ##a## ... ?
Help will be much appreciated ... ...

Peter==========================================================================================

NOTE:

The start of D&K's section on differentiable mappings may help readers of the above post understand the context and notation of the post ... so I am providing the same as follows:
D&K - 1 - Start of Section 2.2 on Differentiable Mappings ... PART 1 ... .png

D&K - 2 - Start of Section 2.2 on Differentiable Mappings ... PART 2 ... .png

The start of D&K's section on linear mappings may also help readers of the above post understand the context and notation of the post ... so I am providing the same as follows:
D&K - 1 -  Linear Mappings ... Start of Section - PART 1.png

D&K - 2 -  Linear Mappings ... Start of Section - PART 2 ... ... .png

D&K - 3 -  Linear Mappings ... Start of Section - PART 3 ... ... .png

Hope the above helps readers understand the context and notation of the post ...

Peter
 

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  • D&K - 1 -  Lemma 2.2.7 ... ... PART 1 ... .png
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  • D&K - 2 -  Lemma 2.2.7 ... ... PART 2 ... .png
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  • D&K - 1 - Start of Section 2.2 on Differentiable Mappings ... PART 1 ... .png
    D&K - 1 - Start of Section 2.2 on Differentiable Mappings ... PART 1 ... .png
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  • D&K - 2 - Start of Section 2.2 on Differentiable Mappings ... PART 2 ... .png
    D&K - 2 - Start of Section 2.2 on Differentiable Mappings ... PART 2 ... .png
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  • D&K - 1 -  Linear Mappings ... Start of Section - PART 1.png
    D&K - 1 - Linear Mappings ... Start of Section - PART 1.png
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  • D&K - 2 -  Linear Mappings ... Start of Section - PART 2 ... ... .png
    D&K - 2 - Linear Mappings ... Start of Section - PART 2 ... ... .png
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  • D&K - 3 -  Linear Mappings ... Start of Section - PART 3 ... ... .png
    D&K - 3 - Linear Mappings ... Start of Section - PART 3 ... ... .png
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Math Amateur said:
" ... ... A direct computation gives##\| \epsilon_a(h) h^t \|_{ Eucl } = \| \epsilon_a(h) \| \| h \|## , (1)

hence

##\lim_{ h \rightarrow 0 } \frac{ \| \epsilon_a(h) h^t \|_{ Eucl } }{ \| h \|^2 } = \lim_{ h \rightarrow 0 } \frac{ \| \epsilon_a(h) \| }{ \| h \| } = 0## (2)This shows that ##\phi_a## is continuous at ##a##. ... ... "

My questions are as follows:

Question 1

... how/why does the above show that ##\phi_a## is continuous at ##a##. ... ...?
Let ##h=x-a##. With that substitution we have

$$\frac{ \| \epsilon_a(h) h^t \|_{ Eucl } }{ \| h \|^2 }
= \frac{ \| \epsilon_a(x-a) (x-a)^t \|_{ Eucl } }{ \|x-a \|^2 }
=\|\phi_a(x)-\phi_a(a)\|
$$
per the above definition of ##\phi_a(x)##

So what you have quoted shows that the limit as ##x\to a## of ##\|\phi_a(x)-\phi_a(a)\|## is zero, which is one way of defining continuity of ##\phi_a## at ##a##..
 
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Thanks Andrew ...

Appreciate your help ...

Peter
 

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