Undergrad Muon Time Dilation in Accelerating Frames

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The discussion centers on the application of the time dilation formula, gamma = sqrt(1 - v^2 / C^2), in the context of muons moving in a circular orbit at high speeds. While the formula is derived for inertial frames, the muons are in an accelerating frame, raising questions about its validity. It is clarified that the elapsed time for a particle can still be expressed using the same formula under certain conditions, assuming velocity is constant over the time interval considered. However, it is noted that the perspective of an observer in the muon's frame differs from that of an inertial observer, leading to non-reciprocal conclusions about time dilation. Ultimately, the reference frame in which the muon's velocity is measured remains an inertial frame, allowing for the application of the time dilation formula.
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In the book, "Why does E= mc2" by Cox and Forshaw, while discussing time dilation, the example of a muon is given. The authors explain that muons when circulated in the 14 m diameter AGS facility at Brookhaven at 99.94% of the speed of light, its lifetime is increased from the value of 2.2 microseconds (when it is at rest) to 60 microseconds i.e 29 times longer which he explains is equal to gamma = sqrt(1 - v^2 / C^2).

My question is : The formula, gamma = sqrt(1 - v^2 / C^2), is for an inertial system while the muons while moving in the circular orbit are in an accelerating frame. So is it correct to use this expression for time dilation ?

Thank you
 
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Yes. The correct general formula is that the elapsed time for a particle is$$\begin{eqnarray*}
\Delta \tau&=&\int_{t=0}^{\Delta t}d\tau\\
&=&\frac{1}{c}\int_{t=0}^{\Delta t}\sqrt{c^2dt^2-dx^2-dy^2-dz^2}\\
&=&\frac 1{c}\int_0^{\Delta t}\sqrt{c^2-\left(\frac{\partial x}{\partial t}\right)^2-\left(\frac{\partial y}{\partial t}\right)^2-\left(\frac{\partial z}{\partial t}\right)^2}dt
\end{eqnarray*}$$But the sum of the squares of the partial derivatives is just the velocity squared, and hence$$\begin{eqnarray*}
\Delta \tau&=&\frac 1c\int_0^{\Delta t}\sqrt{c^2-v^2}dt\\
&=&\sqrt{1-\frac{v^2}{c^2}}\Delta t
\end{eqnarray*}$$Note that I've said nothing about the path beyond assuming that ##v^2## is independent of ##t## in the last step, but have assumed that the ##t,x,y,z## coordinates are inertial coordinates.

Note that this case is not reciprocal. An observer circling with the muon would not conclude that lab clocks were ticking slow, but that they were ticking fast - the muon observer's frame is not inertial. So, while some results for inertial motion do hold for non-inertial motion, not all of them do.
 
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bksree said:
n is : The formula, gamma = sqrt(1 - v^2 / C^2), is for an inertial system while the muons while moving in the circular orbit are in an accelerating frame. So is it correct to use this expression for time dilation ?
The reference frame in which v is measured is an inertial reference frame.
 
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In an inertial frame of reference (IFR), there are two fixed points, A and B, which share an entangled state $$ \frac{1}{\sqrt{2}}(|0>_A|1>_B+|1>_A|0>_B) $$ At point A, a measurement is made. The state then collapses to $$ |a>_A|b>_B, \{a,b\}=\{0,1\} $$ We assume that A has the state ##|a>_A## and B has ##|b>_B## simultaneously, i.e., when their synchronized clocks both read time T However, in other inertial frames, due to the relativity of simultaneity, the moment when B has ##|b>_B##...

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