Must Expectation Values Be Real?

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Expectation values must be real, as they represent weighted averages of possible measurement outcomes, which are inherently real. If an imaginary value is obtained, it indicates a mistake in the calculations, likely due to improper handling of operators. The presence of 'i' in the momentum operator should be resolved through differentiation, eliminating the imaginary component. Complex answers may arise in specific scenarios, such as violations of unitarity, but these will not yield purely imaginary results. Therefore, it is essential to verify calculations to ensure the validity of expectation values.
pivoxa15
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Is it true that all expectation values must be real? So if I get an imaginary value, does it mean I made a mistake? Or it doesn't matter and I can just take the absolute value of the expectation?

The momentum operator has an 'i' in it. But after doing, Psi*[P]Psi, I have an expression with 'i' which means I am left with an imaginary expectation value? What should I do?
 
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pivoxa15 said:
Is it true that all expectation values must be real?
Absolutely. They are weighted averages over possible measurement outcomes. The outcomes are real, the weights (probabilities) are real, so the expectation value has to be real. By the way, this is why the operators associated with observables are self-adjoint. The eigenvalues of operators associated with observables are the possible outcomes of measurements. And eigenvalues of self-adjoint operators are real. See how things hang together?
So if I get an imaginary value, does it mean I made a mistake?
Obviously.
 
I would say that with high probability, you need to go back and redo your calculation.

The "i" in the operator should get eliminated by an i that appears when you apply d/dx to something that looks like exp(ix).

The only time you might legitimately get a complex answer to something like this is when you are violating unitarity (if I recall correctly). That means that probability isn't being conserved, so your problem might involve a radioactive decay. But even then, you won't get a purely imaginary answer.

By the way, there is a pretty good probability that this discussion will get banished to homework land. The basic idea is that if it's not interesting enough to make the local experts call each other names, then it must be homework.

Carl
 
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CarlB said:
By the way, there is a pretty good probability that this discussion will get banished to homework land. The basic idea is that if it's not interesting enough to make the local experts call each other names, then it must be homework.
Carl

HAHA; I like the way you put it!
 
CarlB said:
The basic idea is that if it's not interesting enough to make the local experts call each other names, then it must be homework.
And if it's interesting enough, it may get banished to the philosophy forum! :biggrin:
 
TriTertButoxy said:
HAHA; I like the way you put it!

Yup me too! Anyway check your calculations (as already pointed out...)
 

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