Muzzle Velocity by Analyzing Ballistic Pendulum

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SUMMARY

The discussion focuses on deriving the equation for muzzle velocity using the conservation of energy principle in a ballistic pendulum setup. The key equation proposed is v=sqrt((2*g*h*(Mc+Mb))/Mb), where Mb is the mass of the ball (0.0077 kg), Mc is the mass of the catcher (0.085 kg), g is the acceleration due to gravity, and h is the height of displacement (0.019 m). A discrepancy arises with an alternative equation found online, v=(1+Mc/Mb)*sqrt(2*g*h), prompting further examination of the collision type and conservation laws involved.

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  • Understanding of conservation of energy principles
  • Familiarity with kinetic and potential energy equations
  • Basic knowledge of ballistic pendulum mechanics
  • Ability to perform algebraic manipulations and solve equations
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ujellytek
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Homework Statement


Finding the equation for the muzzle velocity by using conservation of energy.

2. The attempt at a solution

Ek+Eg=Ek2+Eg2
Well I'm 100% sure the kinetic energy of the ball is transferred into the catcher. The displacement is 1.9cm which is 0.019m. Mb=0.0077Kg (mass of ball) Mc=0.085Kg (mass of catcher)

Here is my work: .5Mbv^2=Mc*g*h <- this is supposed to be the total mass because the Mc and Mb become one, right? (btw that's the method my classmates used)
My method: .5Mbv^2=(Mc+Mb)*g*h
eventually v=sqrt( (2*g*h*(Mc+Mb))/Mb )

3. Relevant questions:

Is the proper equation for the muzzle velocity? v=sqrt((2*g*h*(Mc+Mb))/Mb)

I went to check this online, and I found out that the equation is supposedly supposed to be
v=(1+Mc/Mb)*sqrt(2*g*h)
 
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Your problem statement is rather spare. You should describe the setup and define the variables you'll be using.

ujellytek said:
Well I'm 100% sure the kinetic energy of the ball is transferred into the catcher.
You might want to rethink that. What type of collision is involved? What's conserved? What's not conserved?
 
Also, you may just want to double check that all of the values are correct.
 

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