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## Main Question or Discussion Point

Given that

My thoughts:

suppose [tex]\alpha_i[/tex]([tex]1\leq i \leq n-1[/tex]) is the basis of N, the linear functional in question has to satisfy f([tex]\alpha_i[/tex])=0.

Am I correct?

Thanks

*N*is an (n-1)-dimensional subspace of an n-dimensional vector space V, show that*N*is the null space of a linear functional.My thoughts:

suppose [tex]\alpha_i[/tex]([tex]1\leq i \leq n-1[/tex]) is the basis of N, the linear functional in question has to satisfy f([tex]\alpha_i[/tex])=0.

Am I correct?

Thanks