Need an explanation for Null Vectors

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So I have an issue understanding how to compute a matrix using the Minkowski metric as a null (read light-like) spacetime vector.
As best I can understand it, it is a vector which has all velocity in the spatial components and none in time.

Also, would a vector that transcends the speed of light mean that you are traveling through negative time? I don't really get how I should interpret a vector that is inside the light cone.


So I have
[-1 0 0 0]
[0 1 0 0 ]
[0 0 1 0 ]
[0 0 0 1 ]
for my matrix denoting the Minkowski metric (probably using wrong terminology)
what would a vector that determines a null vector be?
 
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Definition of Null Vevtor

$$\Lambda_{\mu\nu}$$ be your matrix, null vector $$x^\mu$$ satisfies the relation

$$x^\mu\Lambda_{\mu\nu} x^\nu=\Lambda_{\mu\nu} x^\nu x^\mu=0$$

Best
 
cy6nu5 said:
So I have an issue understanding how to compute a matrix using the Minkowski metric as a null (read light-like) spacetime vector.
As best I can understand it, it is a vector which has all velocity in the spatial components and none in time.

I'm not sure why you said velocity?, I hope I haven't misunderstood the question as a consquence of assuming you meant component.

A vector with only spacelike components and a zero time component would be a space-like vector, not a null vector.

Also, would a vector that transcends the speed of light mean that you are traveling through negative time? I don't really get how I should interpret a vector that is inside the light cone.

A vector inside the lightcone would also be a spacelike vector, as in your previous example.


So I have
[-1 0 0 0]
[0 1 0 0 ]
[0 0 1 0 ]
[0 0 0 1 ]
for my matrix denoting the Minkowski metric (probably using wrong terminology)
what would a vector that determines a null vector be?[/QUOTE]

An example of a null vector for your metric (which is Minkowskii) would be [1,0,0,1].
If we let X be your vector, with the components of your vector be ##x^0, x^1, x^2, x^3## , and the nonzero components of your matrix (as above) being written in the following notation ##g_{00} = -1, g_{11}=g_{22}=g_{33}=1##, then the length of your vector is

[tex]\sum_{\mu=0..3} \sum_{\nu=0..3} g_{\mu\nu} x^\mu x^\nu[/tex]

which for Minkowskii space is equivalent to

##-(x^0)^2 + (x^1)^2 + (x^2)^2 + (x^3)^2##

and a null vector is just a vector with a length of 0, such as the vector with ##x^0 = x^1 = 1## mentioned previously.
 
cy6nu5 said:
As best I can understand it, it is a vector which has all velocity in the spatial components and none in time.
No. It has a time-like component that equals the magnitude of the space-like component.