MHB Need Assistance - Can Someone Help Me?

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Hi,

can somebody help me with the following problem:View attachment 1530

Thank you. :)
 

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FilipVz said:
Hi,

can somebody help me with the following problem:View attachment 1530

Thank you. :)

Hi Filipvz, :)

Welcome to MHB! :)

You can find the proof for this theorem >>here<<.
 
Lazy, hazy proof:

An isomorphism is, among other things, a bijection. So all one needs to do is show 2 things:

1) A linear injection preserves linear independence
2) A linear surjection preserves spanning

These two facts together show that the image under our given isomorphism of a basis for the first vector space is a basis for the second space, and since the isomorphism is bijective, they have the same cardinality.
 
Thread 'How to define a vector field?'
Hello! In one book I saw that function ##V## of 3 variables ##V_x, V_y, V_z## (vector field in 3D) can be decomposed in a Taylor series without higher-order terms (partial derivative of second power and higher) at point ##(0,0,0)## such way: I think so: higher-order terms can be neglected because partial derivative of second power and higher are equal to 0. Is this true? And how to define vector field correctly for this case? (In the book I found nothing and my attempt was wrong...

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