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**1. Homework Statement**

A 347 kg satellite orbits mercury and makes 6.6 orbits in 1 day.

Mercury ---- Radius 2.44*10^6 meters ----- Mass 3.27*10^23 kg

1.Find the Period of Revolution

2.Calculate the Tangential Velocity

3.Calculate the height above the surface of the planet that the satellite is in orbit

4.Calculate the force of gravity at a distance of 1.50*10^6 meters

**2. Homework Equations**

Planetary motion Equations

**3. The Attempt at a Solution**

1. Period= 24 hours/6.6 orbits ----

**13090.90909 seconds**(per revolution)

2. Tangential Velocity= (2*pi*radius)/Period ----- (2*pi*(2.44*10^6))/13090.90 second ---- Vt=

**1171 m/s**

3. My friend said that this was the equation for the third part, does anyone know if this is right.

h=((Gravity Constant*Mass Mercury)/Vt^2) - radius of Mercury -----

h=((6.67*10^-11)(3.27*10^23)/1171^2) - 2.44*10^6 meters -----

h= 13465956 meters or

**1.3465*10^7 meters**(is this right)!?!

4. Same friend said that the force of gravity would be :

g= (Gravity Constant*Mass Mercury)/((Radius Mercury+Height)^2)

g= (6.67*10^-11)(3.27*10^23)/ ((2.44*10^6+1.5*10^6)^2)

g=

**1.405 m/sec^2**

Can some one check these answers because I just feel like I did something wrong.