Need Help about Deriving Radical.

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SUMMARY

The discussion focuses on deriving the equation T = 2π√(m/k) to express k in terms of T, m, and π. The correct transformation leads to k = 4π²m/T². The process involves isolating the square root by squaring both sides and manipulating the equation through reciprocal operations. Key steps include recognizing the need to square the equation and rearranging terms to achieve the desired form.

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  • Understanding of algebraic manipulation
  • Familiarity with square roots and squaring operations
  • Knowledge of basic physics concepts related to mass (m) and spring constant (k)
  • Ability to work with mathematical constants such as π
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KevinPaul06
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I'm trying to derive T= 2π√m/k to become k= 4π2m/T2

How is that happen? Can someone please explain it to me? Thanks in advance!
 
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So you're starting from:

T = 2n \sqrt{\frac{m}{k}}

The first step would be to isolate the square root. How do you do that?
 
I don't know. I tried to this T=2π (m/k)1/2 to remove the radical. I don't what's next and I'm not even sure if that is really the 1st step.
 
If you have c= ab and want to "isolate" b, divide both sides by a: b= c/a.

If have a square root, y= \sqrt{x}, square both sides: x= y^2

In both cases we are "undoing" what was done by doing the opposite. In "c= ab", b is not isolated because it is multiplied by a. The opposite of "multiply by a" is "divide by a". The opposite of square root is the square.
 
Okay thanks I think I get it.

T= 2π√m/k

(T/2π)2 = √m/k

T2/4π2 = m/k

T2/4π2m = 1/k , then reciprocal both sides.
 
KevinPaul06 said:
Okay thanks I think I get it.

T= 2π√m/k

(T/2π)2 = √m/k
Probably a typo- you mean (T/2\pi)^2= \left(\sqrt{m/k}\right)^2

T2/4π2 = m/k

T2/4π2m = 1/k , then reciprocal both sides.
 

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