Can someone help me solve this? I don't really understand how to do this. A 1kvA reactor's capacity is needed to be enlargedto 81kvA. How much does its dimension needs to be multiplied? Hint: when its dimension is m times enlargened, surface A'=m'A, flux ∅'=m^2∅, current I'=m^2I, voltage E'=m^2E, Capacity E'I'=m^4EI. Loss Pe'=m^3Pe Temperature θ'=loss/surface area = (m^3Pe)/m^2A = mθ My attempt: Capacity E'I'=m^4EI. So, E'I' / EI = m^4 81/1 = m^4 m = 3. Is the answer 3?