NEED Help (Basically a Law of Cosines problem)

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[SOLVED] NEED Help (Basically a Law of Cosines problem)

So in this problem, all I have to do is to solve it is find out by how much cables AC and AB elongate.
Picture4.png


I thought I could just break it into two Right triangles and just use similar triangles (before and after elongation)

If you look at the upper right triangle, let's call it ACO, where O denotes the point on the wall halfway between C and B.

Then I tried doing,
[tex]\frac{AC}{OA}=\frac{AC'}{OA'}[/tex]

[tex]\Rightarrow AC'=\frac{300}{300\cos30}*(300\cos30+2)[/tex]

But this does not work. . . why the hell not??

My prof gave us the hint: "Use Law of Cosines to find the lengths of AC or AB after elongation"

How do I use Law of Cos if I don't know the angles after elongation, and moreover what is wrong with the process I tried?

I hate all of my classes. I miss physics.

Casey
 
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Mechanics of Materials eh?

http://www.mediafire.com/?0fmwmgeogi6
 
Last edited by a moderator:
Where did you get that? Anyway, thanks! I think the dotted line should be labeled [itex]L_{AC}'[/itex] though. But now I see it. I never took a geometry course so this stuff makes me insane.

Do you know why my original method does not work?
 
because they won't be similar triangles...
 
coffeebean51 said:
because they won't be similar triangles...

ummm. . . because the angle changes right?
 
Short and to the point. I like your style beans :wink:

Welcome aboard,
Casey