MHB Need help factoring and understanding Grouping

  • Thread starter Thread starter hououin kyouma1
  • Start date Start date
  • Tags Tags
    Factoring Grouping
hououin kyouma1
Messages
1
Reaction score
0
I need to factor 6t^2+17t+7 when I break down the equation I get 6t^2+3t+14t+7 now I am not sure what to do after that to get my answer can someone please explain the steps for me thank you!
 
Mathematics news on Phys.org
hououin kyouma said:
I need to factor 6t^2+17t+7 when I break down the equation I get 6t^2+3t+14t+7 now I am not sure what to do after that to get my answer can someone please explain the steps for me thank you!

Factorise the first two terms, and factorise the second two terms. Then you should see a common factor.
 
hououin kyouma said:
I need to factor 6t^2+17t+7 when I break down the equation I get 6t^2+3t+14t+7
I presume you wrote it that way because you can now factor "3t" out of "6t^2+ 3t and factor "7" out of "14t+ 7". What does that leave?

now I am not sure what to do after that to get my answer can someone please explain the steps for me thank you!
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.

Similar threads

Replies
3
Views
873
Replies
6
Views
2K
Replies
3
Views
964
Replies
15
Views
4K
Replies
1
Views
1K
Replies
4
Views
2K
Replies
11
Views
3K
Back
Top