Need help factoring and understanding Grouping

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    Factoring Grouping
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SUMMARY

The discussion focuses on factoring the quadratic expression 6t² + 17t + 7. The user initially breaks it down into 6t² + 3t + 14t + 7, which is a correct step. The next steps involve factoring the first two terms to get 3t(2t + 1) and the second two terms to get 7(2t + 1), leading to the final factored form of (3t + 7)(2t + 1).

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hououin kyouma1
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I need to factor 6t^2+17t+7 when I break down the equation I get 6t^2+3t+14t+7 now I am not sure what to do after that to get my answer can someone please explain the steps for me thank you!
 
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hououin kyouma said:
I need to factor 6t^2+17t+7 when I break down the equation I get 6t^2+3t+14t+7 now I am not sure what to do after that to get my answer can someone please explain the steps for me thank you!

Factorise the first two terms, and factorise the second two terms. Then you should see a common factor.
 
hououin kyouma said:
I need to factor 6t^2+17t+7 when I break down the equation I get 6t^2+3t+14t+7
I presume you wrote it that way because you can now factor "3t" out of "6t^2+ 3t and factor "7" out of "14t+ 7". What does that leave?

now I am not sure what to do after that to get my answer can someone please explain the steps for me thank you!
 

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