Need help finding the max velocity I can drive without flying off a hill

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Homework Help Overview

The discussion revolves around determining the maximum speed a car can travel over the top of a hill modeled as a circular arc with a radius of 50 meters, without losing contact with the road. The problem is situated within the context of circular motion and forces acting on the car.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between forces required for circular motion and the conditions under which a car remains on the road. Questions arise regarding the necessity of mass in calculations, the role of gravitational force, and the derivation of relevant equations.

Discussion Status

The discussion is active, with participants sharing insights about centripetal force and gravitational force. Some guidance has been provided regarding the relationship between these forces and the conditions for maintaining circular motion. There is an ongoing exploration of critical speed and its implications for the problem.

Contextual Notes

Participants note the absence of a coefficient of friction and express uncertainty about its relevance. There is also mention of previous difficulties with related concepts in circular motion, which may influence understanding.

Coronita
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A car drives over the top of a hill that has a radius of 50m. What maximum speed can the car have without flying off the road at the top fo the hill?

Soooo I know I'm supposed to treat the hill like a circle...no coefficient of friction given, not sure if I need that though, not really sure what direction to go in here, please help?
 
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What is the magnitude of force required to keep an object in circular motion with radius r?
 
it's not 2pi r/t is it?
 
Coronita said:
it's not 2pi r/t is it?

That's not a force, check the units. You need to go back and review circular motion to answer the question.
 
I've been looking through the chapter on circular motion but all I've got are the rotational kinematic equations, I struggled with that chapter when we covered it too and that was 4 chapters ago >_<
 
k, best I've got is F=mv^2/r but I don't know the mass of the car, I can't just consider it to be mass-less can I?
 
Coronita said:
k, best I've got is F=mv^2/r but I don't know the mass of the car, I can't just consider it to be mass-less can I?

Just keep the mass as an unknown at this point. Now consider the force diagram for the car. Can you find an equation that must be satisfied for the car to remain in circular motion?
 
? :(
 
What force or forces act on the car?
 
  • #10
kinetic friction, normal and gravity
 
  • #11
We're interested in the forces in the vertical direction, which corresponds to forces in the radial direction if we view this as a circular motion problem. Can you include the centripetal force in an equation describing the car when it remains in circular motion?
 
  • #12
I've found the equation for critical speed inside of a circle, Vc=rg^1/2 is it related to that at all?
 
  • #13
Coronita said:
I've found the equation for critical speed inside of a circle, Vc=rg^1/2 is it related to that at all?

Yes, I'm trying to help you derive (and understand) that result.
 
  • #14
I've read through this section of the chatper a few times but I'm still not understanding why it's true
 
  • #15
Well the centripetal force

F_c = \frac{mv^2}{r}

is the radial force required to maintain circular motion. In the case of the car, this force must come from gravity. For slow speeds, the gravitational force,

F_g=mg,

will generally be greater than the required centripetal force, so the car stays on the ground. For high enough speeds, the required centripetal force will be higher than Fg, and the car will hop off the ground. If the critical speed is the maximum speed before the car leaves the ground, can you guess what condition on the forces must be satisfied at the critical speed?
 
  • #16
Gravity must still be greater than the centripetal force. So we're looking for the point at which centripetal force is the closest it can get to Fc without surpassing it?
 
  • #17
I have to be somewhere in 20 minutes >_< Thank you so much for your patience though! I'll have to come back to this one later.
 

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