Need help. How do i start the problem, thank you.

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SUMMARY

The discussion centers on a physics problem involving a basketball player who performs 2.43 x 105 J of work and evaporates 0.110 kg of water, with a latent heat of 2.26 x 106 J/kg. The key equations referenced include the first law of thermodynamics, specifically ΔU = Q - W, which is essential for determining changes in internal energy. Participants suggest calculating the latent heat associated with the water evaporation to find the net energy loss, which will lead to the solution of the problem.

PREREQUISITES
  • Understanding of the first law of thermodynamics
  • Knowledge of latent heat and its significance in phase transitions
  • Ability to perform calculations involving energy, work, and heat
  • Familiarity with basic physics concepts related to energy transfer
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  • Calculate the latent heat for the evaporation of water using the formula Q = mL
  • Apply the first law of thermodynamics to find the change in internal energy
  • Convert the energy calculated into nutritional calories
  • Explore additional examples of energy transfer in biological systems
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Students studying thermodynamics, physics educators, and anyone interested in understanding energy transfer in biological systems, particularly in sports science contexts.

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Homework Statement



A basketball player does 2.43 X 105 J of work during her time in the game, and evaporates 0.110 kg of water. Assuming latent heat of 2.26 X 106 J/kg for the perspiration (the same as for water), (a) determine the change in the player’s internal energy, and (b) the number of nutritional calories the player has converted to work and heat.


Homework Equations


First law of thermodynamics
U = Q-W


The Attempt at a Solution


I need help on how to start it and what they mean by latent heat. Thank you
 
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The latent heat is the amount of energy absorbed or emitted by a system during a phase transition (liquid -> solid, say) carried out at constant temperature.

You should proceed in calculating what the latent heat is in this instance; then it should be fairly obvious what to do ;)


R.
 
just calculate net latent heat and this with the work done would be the net loss
 

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