Need help in finding extreme values

  • Thread starter Thread starter aruwin
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  • #51
aruwin said:
Given the equation x^2+y^2+3z^2-2xy-2yz=2.Find the local extrema for the function z=f(x,y).What do I do with the equation?

What do you get when you take the partial derivatives?
 
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  • #52
haruspex said:
What do you get when you take the partial derivatives?
Is this ok?
Partial derivative in respect to x is 2x-2y and in respect to y is 4y-2x-2z.
What do I do with z??
 
  • #53
aruwin said:
Thanks for all your explanations and patience.Yes,I have solved this question with your help and harupex too.By the wsy,I have a new question.Since it is related to finding local extrema too,I am just going to ask it here.
Given the equation x^2+y^2+3z^2-2xy-2yz=2.Find the local extrema for the function z=f(x,y).What do I do with the equation?
You want to differentiate z with respect to x and y and can do that using "implicit differentiation" just like you learned in Calculus I.
 
  • #54
aruwin said:
Is this ok?
Partial derivative in respect to x is 2x-2y and in respect to y is 4y-2x-2z.
What do I do with z??

Partial derivative of z wrt x is ∂z/∂x, etc. Just treat that as a variable. You can differentiate it partially wrt x again, ∂2z/∂x2, or wrt y: ∂2z/∂x∂y. (Btw, ∂2z/∂x∂y = ∂2z/∂y∂x)
 

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