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Need help in Phase of time in SHM

  1. Apr 27, 2015 #1
    Hi, I'm very confused about one question in my homework, that is due today.
    I appreciate any help.Thank you very much.

    1. The problem statement, all variables and given/known data

    The motion of a particle is given by: x = (6.0m) cos(0.586t + 0.72)
    Find the phase at time t=1.38s

    2. Relevant equations

    Simple harmonic motion

    3. The attempt at a solution
    I found the point 0.25262 m and the phase 2pi(1.38)/10.72
     
  2. jcsd
  3. Apr 27, 2015 #2

    robphy

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    The "phase [angle]" is [usually] the expression inside the the cosine function: (0.586*t+0.72) radians.
    So, your point is the position at t=1.38s. However, you didn't correctly identify the phase.

    I say "usually" because some texts might have defined it using another function (like the sine function).
     
  4. Apr 27, 2015 #3
    thanks
     
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