Phase of Simple Harmonic Motion: Determining the Phase at a Specific Time

Click For Summary

Homework Help Overview

The discussion revolves around determining the phase of a body oscillating in simple harmonic motion (SHM) based on its displacement equation, specifically at a given time of 2 seconds.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculation of the phase by substituting the time into the displacement equation. Questions arise regarding whether the phase is simply the expression within the brackets of the sine function.

Discussion Status

Some participants have provided insights into the relationship between the phase angle and the sine function, while others express uncertainty about the general definition of phase in different contexts. The conversation is ongoing with various interpretations being explored.

Contextual Notes

There is mention of a specific answer being expected, and some participants question the generality of the phase definition in relation to SHM.

sugz
Messages
110
Reaction score
0

Homework Statement


A body oscillates with simple harmonic motion along the x-axis. Its displacement varies with time according to the equation x = 5sin(pi*t + pi/3). The phase (in rad) of the motion at t = 2s is

a) (7pi)/3 b) pi/3 c) pi d) (5pi)/3 e) 2pi

Homework Equations

The Attempt at a Solution


I plugged in the value for t=2 but I really did not know how to past this point. The answer is supposed to be a)
 
Physics news on Phys.org
sugz said:

Homework Statement


A body oscillates with simple harmonic motion along the x-axis. Its displacement varies with time according to the equation x = 5sin(pi*t + pi/3). The phase (in rad) of the motion at t = 2s is

a) (7pi)/3 b) pi/3 c) pi d) (5pi)/3 e) 2pi

Homework Equations

The Attempt at a Solution


I plugged in the value for t=2 but I really did not know how to past this point. The answer is supposed to be a)

Please show your work. What do you get for x(2)?
 
x(2) = 4.33. But how do I determine the phase? Is the phase simply what is in the brackets? So the phase is equal to 2pi+(pi/3)?
 
sugz said:
So the phase is equal to 2pi+(pi/3)?

Yes. What is that in radians?
 
Its 7pi/3. So for any equation of a particle in SHM, the phase is the part inside the brackets?
 
sugz said:
Its 7pi/3. So for any equation of a particle in SHM, the phase is the part inside the brackets?

Sort of. For a sinusoidal function (sin or cos), you can picture the value in 2-dimensions on a circle. The amplitude is the radius of the circle, and the point that rotates around the circle with time has some phase angle θ with the positive horizontal axis. If you have a sin() function like you do in this problem, then yes, the value in the () is the phase angle θ with the horizontal axis.

http://images.tutorcircle.com/cms/images/106/unit-circle-example.png
 

Attachments

  • unit-circle-example.jpg
    unit-circle-example.jpg
    7.3 KB · Views: 693
Now I understand, thank you so much!
 
It may be true in general, but sometimes we define phase with respect to something, so I'm not sure it is a general statement. Others can correct that if appropriate. :smile:
 

Similar threads

  • · Replies 51 ·
2
Replies
51
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
16
Views
2K
  • · Replies 8 ·
Replies
8
Views
5K