What are the products of the reaction: SnCl4 + CH3OH + N2 + H2O?

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SUMMARY

The reaction between SnCl4 and CH3OH in the presence of nitrogen and water yields formaldehyde (HCHO), SnCl2, protons (H+), and chloride ions (Cl–). SnCl4 acts as a mild oxidant, oxidizing methanol to formaldehyde while nitrogen is bubbled through to eliminate dissolved oxygen, preventing further oxidation to formic acid (HCOOH). This reaction is relevant in thin film technology, where formaldehyde can be utilized as a cross-linking agent for polymers.

PREREQUISITES
  • Understanding of SnCl4 as a mild oxidant
  • Knowledge of methanol (CH3OH) oxidation reactions
  • Familiarity with the role of nitrogen in chemical reactions
  • Basic principles of thin film technology
NEXT STEPS
  • Research the oxidation of methanol to formaldehyde using SnCl4
  • Explore the applications of formaldehyde in polymer chemistry
  • Investigate the effects of nitrogen bubbling in chemical reactions
  • Learn about the synthesis and properties of network polymers
USEFUL FOR

Chemists, materials scientists, and professionals in thin film technology will benefit from this discussion, particularly those interested in oxidation reactions and polymer applications.

citoca
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Please what are the products of this reaction; SnCL4 + CH3OH + N2 + H2O .
 
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I have some ideas about the answer, but can you provide a context for how the question arises? I cannot see how nitrogen can possibly be involved in any reaction, but can see why you might be bubbling nitrogen through the reaction mixture. Similarly water is unlikely to have direct involvement.
 
JohnRC said:
I have some ideas about the answer, but can you provide a context for how the question arises? I cannot see how nitrogen can possibly be involved in any reaction, but can see why you might be bubbling nitrogen through the reaction mixture. Similarly water is unlikely to have direct involvement.

This is for thin film technology.
 
OK then. I think the reaction you are wanting is carried out in aqueous solution with nitrogen bubbling through. The SnCl4 is a mild oxidant, designed to oxidize the methanol CH3OH to formaldehyde HCHO. Nitrogen is bubbled through the solution to remove dissolved oxygen, and prevent the oxidation reaction going further to formic acid HCOOH.

The reaction is SnCl4 + CH3OH → HCHO + SnCl2 + 2 H+ + 2 Cl.

Formaldehyde forms network polymers when reacted with phenol or melamine or similar materials. It might also be used as a cross-linking agent to harden some of the films you are working with.

(Reason for asking my previous question was that I wanted to try to check that this was not homework before "spilling the beans".:smile:)
 
Last edited:
JohnRC said:
(Reason for asking my previous question was that I wanted to try to check that this was not homework before "spilling the beans".:smile:)

You will be surprised when you learn what lies people tell to pretend the problem is not their homework.

- Mrs. Teacher? John is sick and he will not come to school today.
- Who is speaking?
- What do you mean "who is speaking"? My father!
 
Yeah, I did say "trying to check"!
 
I came.across a headline and read some of the article, so I was curious. Scientists discover that gold is a 'reactive metal' by accidentally creating a new material in the lab https://www.earth.com/news/discovery-that-gold-is-reactive-metal-by-creating-gold-hydride-in-lab-experiment/ From SLAC - A SLAC team unexpectedly formed gold hydride in an experiment that could pave the way for studying materials under extreme conditions like those found inside certain planets and stars undergoing...

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