Need help solving a trigonomic equation

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Homework Help Overview

The discussion revolves around solving a trigonometric equation involving sine and cosine functions, specifically: 0.5*cos(x) - 0.875*sin(x)*cos(x) + A*sin^2(x) = A. The original poster, a mechanical engineer, expresses difficulty in finding the value of x after several attempts.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants explore algebraic manipulation of the equation, including collecting terms involving A and applying the Pythagorean identity. There are discussions about assuming cos(x) is not zero and dividing by cos(x) to find solutions. One participant suggests a method to express a linear combination of sine and cosine as a single sinusoid.

Discussion Status

The discussion has progressed with participants offering algebraic insights and alternative approaches. While one participant expresses gratitude for the guidance received, indicating some level of understanding, there remains uncertainty as they continue to struggle with a derived equation.

Contextual Notes

The original poster mentions a lack of time to detail all previous attempts, indicating constraints in their ability to share comprehensive information. There is also a suggestion that the problem may involve complexities that could lead to messy solutions.

unicycle6869
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I hope I'm posting this in the correct spot?!

I just got hired a few months ago as an mechanical engineer at a small start up company and need help solving an equation that I've spent hours after hours on trying to figure out. If anyone could offer advice and or steps to get the solution I'd very much appreciate it. I think I've tried almost everything but apparently not cause I can't figure out how to solve for x. Here is the equation: 0.5*cos(x)-0.875*sin(x)*cos(x)+A*sin^2(x)=A

I'd show you all the steps I've tried but it would take me several hours to type them all in here. I tried converting everything to both sin and cos but that didn't seem to work. Thanks in advance to any geniouses out there...
 
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Notice that if you collect terms with A, you get [itex]A(1-sin(x)^2)=Acos^2(x)[/itex], since sin^2(x)+cos^2(x)=1

Then you have
[tex](\frac{1}{2}-\frac{7}{8}\sin(x))\cos(x)=A\cos^2(x)[/tex]

So all x for which cos(x)=0 are solutions.
To find other solutions, assume cos(x) is not 0 and divide both sides by cos(x). You can take it from there.
 
Galileo said:
Notice that if you collect terms with A, you get [itex]A(1-sin(x)^2)=Acos^2(x)[/itex], since sin^2(x)+cos^2(x)=1

Then you have
[tex](\frac{1}{2}-\frac{7}{8}\sin(x))\cos(x)=A\cos^2(x)[/tex]

So all x for which cos(x)=0 are solutions.
To find other solutions, assume cos(x) is not 0 and divide both sides by cos(x). You can take it from there.

Thank you so much, that helps! Can't believe I didn't see that. But I'm still struggling... I end up getting this equations which I can't figure out how to solve (it's been a few years...):
4=7*sin(x)+8*A*cos(x)
I'm probably missing something very simple here I'm guessing?
 
A linear combination of a sine and a cosine is again a sinusoid with the same period. I suppose you could use:
[tex]a\cos(x)+b\sin(x)=\sqrt{a^2+b^2}\cos(x-\phi)[/tex]
where
[tex]\phi=\arctan(b/a)[/tex]

It looks nice, but I`m afraid it will be messy.
 
Thank you so much Galileo. You truly helped me out a ton and I was able to find the solution with your help. Rock on. Case closed.
 

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