- #1
immuno
- 4
- 0
Hi guys
i'm having much difficulties in understanding the relations between half life, decay constant and activity.
I'll explain what i known here.
[tex]T^{\frac{1}{2}}[/tex] is the half life which is the time to reduce the nuclides by half.
[tex]\lambda[/tex] is the decay constant which can be solved from
[tex]\lambda[/tex] = 0.693/ [tex]T^{\frac{1}{2}}[/tex]. Am i correct? Where do 0.693 come from?
The decay/sec can be find out using [tex]A = -\frac{dN}{dt} = \lambda N[/tex] if the half life and N is known.
I want to clarify N is in grams? So like 10g of C14 would be the No?
I don't really understand this equation:
[tex]
\frac{dN}{dt} = -\lambda N
[/tex]
i know why it is negative [tex] \lambda N [/tex] as it's decreasing exponentially but what do the d and t stands for? Does the t stands for the half life? What is the use of the equation?
Thanks a bunch!
i'm having much difficulties in understanding the relations between half life, decay constant and activity.
I'll explain what i known here.
[tex]T^{\frac{1}{2}}[/tex] is the half life which is the time to reduce the nuclides by half.
[tex]\lambda[/tex] is the decay constant which can be solved from
[tex]\lambda[/tex] = 0.693/ [tex]T^{\frac{1}{2}}[/tex]. Am i correct? Where do 0.693 come from?
The decay/sec can be find out using [tex]A = -\frac{dN}{dt} = \lambda N[/tex] if the half life and N is known.
I want to clarify N is in grams? So like 10g of C14 would be the No?
I don't really understand this equation:
[tex]
\frac{dN}{dt} = -\lambda N
[/tex]
i know why it is negative [tex] \lambda N [/tex] as it's decreasing exponentially but what do the d and t stands for? Does the t stands for the half life? What is the use of the equation?
Thanks a bunch!