How Fast is the River Current Where the Sunbather Overtakes the Raft?

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Homework Help Overview

The problem involves a sunbather swimming against the current of a river after diving off a raft, with the goal of determining the speed of the river current based on her movements relative to the raft and a bridge.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various attempts to set up equations based on the sunbather's swimming and the raft's movement. There are questions about the adequacy of the provided data and the relationships between the variables involved.

Discussion Status

Some participants have shared their attempts at formulating equations but express uncertainty about the direction of their reasoning. There is recognition of a potential lack of sufficient data to solve the problem definitively, with one participant noting the presence of multiple unknowns.

Contextual Notes

Participants mention the challenge of having three equations with four unknowns, indicating a possible gap in the information needed to reach a solution.

Lisa... needs help
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Hey, I'm practising some exam review questions that i was given but i can't figure this one out

A sunbather, drifting downstream on a raft, dives off the raft just as it passes under a briidge and swims against the current for 15 mins. She then turns and swims downstream, making the same total effort and over taking the raft when it is 1.0km downstream from the bridge. What is the speed of the current in the river?

If someone could help me that would be great!
 
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How about Lisa...offers help?? :-p

We're not going to do the problem for you.We'll only help,if you get stuck.By the looks of it,you haven't even started...
Post you work...


Daniel.
 
opps sorry - i have tried it - many times!?
okay... i tried making up different formulas and substituting them into each other such as:
d1=(Vs-Vc)(900s)
d2=(Vs+Vc)t
d1=d2 (for the time before she gets back to the bridge)
900Vs-900Vc=Vst+Vct
and then i didn't know where to go from there?

i also tried:
d1=(Vs-Vc)(900s) -> Vs=(d/900)+Vc
d2=(Vs+Vc)t -> Vs=(d/t)-Vc

Vs=Vs
and got it down to
(d1/900)+2Vc=(d2/t)

I've tried many other similar ways, but I'm not really sure if I'm heading in the right direction, messing up on the math or what?
 
No,you're not messing up the math,it's just that,the way i see it,it's too little data.I get 3 equations with 4 unknowns.And i can't solve them...

Maybe I'm missing something,but i double checked and still another equation is absent...

Daniel.
 

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