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Need help with derivation of the range formula

  • Thread starter Yorganda
  • Start date
2
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I need to find a derivation of the range formula for a projectile in the absence of air.

i know that the range formula is Range=Vhxt
i know that Vh=vcostheta

but in having trouble understanding how V=Vo+at can be re-arranged to = 2Vsintheta/g=t where a=g=9.8m/s/s (gravity)

i know V=Vo+at can be arranged to equal V-Vo/g=t
but this is where i get stuck, i dont know how to get to V-Vo=2Vsintheta

i know that vsintheta = vertical velocity

If anyone can help it would be appreciated heaps
 
Last edited:

Answers and Replies

Hi,

If you take downward direction to be +ve then

[tex]V=vsin \theta[/tex]

and

[tex]V_o=-v sin \theta[/tex]

a=g :smile:

Put this in your equation.
 

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