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Need help with derivation of the range formula

  1. Mar 26, 2008 #1
    I need to find a derivation of the range formula for a projectile in the absence of air.

    i know that the range formula is Range=Vhxt
    i know that Vh=vcostheta

    but in having trouble understanding how V=Vo+at can be re-arranged to = 2Vsintheta/g=t where a=g=9.8m/s/s (gravity)

    i know V=Vo+at can be arranged to equal V-Vo/g=t
    but this is where i get stuck, i dont know how to get to V-Vo=2Vsintheta

    i know that vsintheta = vertical velocity

    If anyone can help it would be appreciated heaps
    Last edited: Mar 26, 2008
  2. jcsd
  3. Mar 26, 2008 #2

    If you take downward direction to be +ve then

    [tex]V=vsin \theta[/tex]


    [tex]V_o=-v sin \theta[/tex]

    a=g :smile:

    Put this in your equation.
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