Need help with Gravitational Field Strength question

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SUMMARY

The gravitational field strength at a satellite orbiting Earth at a distance of 3 times the Earth's radius (3rEARTH) can be calculated using the formula g' = GM(Earth) / d². Given that the Earth's radius is approximately 6400 km and the gravitational constant G is 6.67 x 10^-11 N(m/kg)², the gravitational field strength decreases with the square of the distance from the Earth's center. The relationship g'/g = R²/d² illustrates this inverse proportionality, confirming that the gravitational field strength at the satellite's position is significantly lower than at the Earth's surface.

PREREQUISITES
  • Understanding of gravitational force equations, specifically Fg = Gm1m2/d²
  • Knowledge of gravitational field strength concepts and calculations
  • Familiarity with the Earth's radius and gravitational constant values
  • Basic algebra for manipulating equations
NEXT STEPS
  • Calculate gravitational field strength at various distances using g' = GM(Earth) / d²
  • Explore the implications of gravitational field strength on satellite orbits
  • Learn about the effects of distance on gravitational force between two masses
  • Investigate the relationship between gravitational field strength and orbital mechanics
USEFUL FOR

Students studying physics, particularly those focusing on gravitational forces and satellite dynamics, as well as educators seeking to clarify concepts related to gravitational field strength.

ultimatesoulx
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Homework Statement


A satellite orbites Earth at a distance of 3rEARTH, above Earth's surface. What is the magnitude of gravitational field strength at the point where the satellite is?

Homework Equations


Fg= Gm1m2/d^2 (m1=mass 1, m2=mass2)
F1/F2 = D2^2/D2^2 (D1 is a variable, and so is D2, so it represents Distance 1 and Distance 2)

The Attempt at a Solution


I don't understand how it works? You have the equation for the radius of Earth, 6400km, but not much else other than the G which is 6.67x10^-11. I'm not sure how to tackle this, and it's confusing me a lot. I tried applying Fg= Gm1m2/d^2, but there is no mass on them.P.s on a secondary note, if I am doing a question where it compares 2 masses that have an attraction (i.e 36N, how do you find the distances/mass?)
 
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ultimatesoulx said:

Homework Statement


A satellite orbites Earth at a distance of 3rEARTH, above Earth's surface. What is the magnitude of gravitational field strength at the point where the satellite is?


Homework Equations


Fg= Gm1m2/d^2 (m1=mass 1, m2=mass2)
F1/F2 = D2^2/D2^2 (D1 is a variable, and so is D2, so it represents Distance 1 and Distance 2)


The Attempt at a Solution


I don't understand how it works? You have the equation for the radius of Earth, 6400km, but not much else other than the G which is 6.67x10^-11. I'm not sure how to tackle this, and it's confusing me a lot. I tried applying Fg= Gm1m2/d^2, but there is no mass on them.


P.s on a secondary note, if I am doing a question where it compares 2 masses that have an attraction (i.e 36N, how do you find the distances/mass?)

The gravitational attraction between masses m1 and m2, d distance apart, is F=Gm1m2/d2. If the objects are spheres d means the distance between their centres.

The gravitational field strength means the force of gravity exerted on unit mass. At the surface of the Earth it is g=9.8 m/s2:

9.8=GM(Earth)/R2, where R is the radius of the Earth.

The gravitational field strength at distance d from the centre of Earth is g'=GM(Earth) /d2.
If you divide the equations in bold you get

g'/9.8=R2/d2.

The satellite is 3R above the surface of Earth. How far is it from the centre of Earth?

ehild
 
The gravity of the Earth at some distance is inversely proportional to the square of the distance from its center. At the surface, this is g. That, and the distance of the satellite from the Earth, should be enough.
 
I understand the question now, thanks for the help!
 

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