Need help with Gravitational Field Strength question

In summary, the magnitude of gravitational field strength at the point where the satellite is located is inversely proportional to the square of the distance from the center of Earth. At the surface of Earth, this is equal to g=9.8 m/s^2, while at a distance of 3 times the radius of Earth, it is equal to g'=9.8/9=1.09 m/s^2. This means that the gravitational field strength decreases with distance from the center of Earth.
  • #1
ultimatesoulx
5
0

Homework Statement


A satellite orbites Earth at a distance of 3rEARTH, above Earth's surface. What is the magnitude of gravitational field strength at the point where the satellite is?

Homework Equations


Fg= Gm1m2/d^2 (m1=mass 1, m2=mass2)
F1/F2 = D2^2/D2^2 (D1 is a variable, and so is D2, so it represents Distance 1 and Distance 2)

The Attempt at a Solution


I don't understand how it works? You have the equation for the radius of Earth, 6400km, but not much else other than the G which is 6.67x10^-11. I'm not sure how to tackle this, and it's confusing me a lot. I tried applying Fg= Gm1m2/d^2, but there is no mass on them.P.s on a secondary note, if I am doing a question where it compares 2 masses that have an attraction (i.e 36N, how do you find the distances/mass?)
 
Physics news on Phys.org
  • #2
ultimatesoulx said:

Homework Statement


A satellite orbites Earth at a distance of 3rEARTH, above Earth's surface. What is the magnitude of gravitational field strength at the point where the satellite is?


Homework Equations


Fg= Gm1m2/d^2 (m1=mass 1, m2=mass2)
F1/F2 = D2^2/D2^2 (D1 is a variable, and so is D2, so it represents Distance 1 and Distance 2)


The Attempt at a Solution


I don't understand how it works? You have the equation for the radius of Earth, 6400km, but not much else other than the G which is 6.67x10^-11. I'm not sure how to tackle this, and it's confusing me a lot. I tried applying Fg= Gm1m2/d^2, but there is no mass on them.


P.s on a secondary note, if I am doing a question where it compares 2 masses that have an attraction (i.e 36N, how do you find the distances/mass?)

The gravitational attraction between masses m1 and m2, d distance apart, is F=Gm1m2/d2. If the objects are spheres d means the distance between their centres.

The gravitational field strength means the force of gravity exerted on unit mass. At the surface of the Earth it is g=9.8 m/s2:

9.8=GM(Earth)/R2, where R is the radius of the Earth.

The gravitational field strength at distance d from the centre of Earth is g'=GM(Earth) /d2.
If you divide the equations in bold you get

g'/9.8=R2/d2.

The satellite is 3R above the surface of Earth. How far is it from the centre of Earth?

ehild
 
  • #3
The gravity of the Earth at some distance is inversely proportional to the square of the distance from its center. At the surface, this is g. That, and the distance of the satellite from the Earth, should be enough.
 
  • #4
I understand the question now, thanks for the help!
 
  • #5


Hi there,

Thank you for reaching out for help with your gravitational field strength question. I can understand how this topic can be confusing, but let me try to explain it to you in a simpler way.

First, let's start with the equation you mentioned: Fg= Gm1m2/d^2. This is the equation for the gravitational force between two objects, where G is the universal gravitational constant (6.67x10^-11), m1 and m2 are the masses of the two objects, and d is the distance between them.

In this case, we are dealing with a satellite orbiting Earth at a distance of 3rEARTH, which is three times the radius of Earth. So, we can rewrite the equation as follows:

Fg= GmEARTHmsatellite/(3rEARTH)^2

Where mEARTH is the mass of Earth and msatellite is the mass of the satellite. Now, since we are only interested in the magnitude of the gravitational field strength, we can simplify this equation further by dividing both sides by msatellite:

Fg/msatellite= GmEARTH/(3rEARTH)^2

Now, let's plug in the values for G (6.67x10^-11) and the radius of Earth (6400km) to get:

Fg/msatellite= (6.67x10^-11)(5.97x10^24kg)/(3(6400km))^2

Note: I converted the mass of Earth from kg to g (5.97x10^24kg = 5.97x10^27g) so that the units will match.

Now, we can solve for the magnitude of the gravitational field strength (Fg/msatellite):

Fg/msatellite= 0.0098 N/kg

Therefore, the magnitude of the gravitational field strength at the point where the satellite is orbiting is 0.0098 N/kg. This means that for every kilogram of mass on the satellite, there is a gravitational force of 0.0098 Newtons pulling it towards the center of Earth.

I hope this explanation helps you understand the concept of gravitational field strength better. As for your secondary question, if you are given a gravitational force (e.g. 36N) and you want to find the distance/mass, you will need to rearrange the equation Fg= Gm
 

1. What is gravitational field strength?

Gravitational field strength is a measurement of the force of gravity at a given point in space. It is often represented by the symbol 'g' and is measured in units of meters per second squared (m/s²).

2. How is gravitational field strength related to mass?

The gravitational field strength at a given point is directly proportional to the mass of the object creating the gravitational field. This means that as the mass of the object increases, the gravitational field strength also increases.

3. What factors affect the gravitational field strength?

The gravitational field strength is affected by two main factors: the mass of the object creating the gravitational field and the distance from that object. The greater the mass, the stronger the gravitational field, and the closer an object is to the source of the field, the stronger the gravitational force.

4. How is gravitational field strength measured?

Gravitational field strength can be measured using a device called a gravimeter. This instrument measures the acceleration due to gravity at a specific location, which can then be used to calculate the gravitational field strength.

5. How does gravitational field strength differ on different planets?

The gravitational field strength on different planets can vary greatly due to differences in mass and distance from the planet's center. For example, the gravitational field strength on Earth is 9.8 m/s², while on the moon it is only 1.6 m/s². This means that objects will weigh less on the moon compared to Earth due to the weaker gravitational pull.

Similar threads

  • Introductory Physics Homework Help
Replies
4
Views
767
  • Introductory Physics Homework Help
Replies
23
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
9
Views
3K
  • Introductory Physics Homework Help
Replies
3
Views
838
Replies
11
Views
1K
  • Introductory Physics Homework Help
Replies
17
Views
2K
  • Introductory Physics Homework Help
Replies
17
Views
2K
  • Introductory Physics Homework Help
Replies
13
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
2K
Back
Top