Need help with integration position vector question

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The discussion focuses on solving a physics problem involving integration of a position vector given an acceleration vector of -g\vec{j}. The velocity vector is derived as -gt\vec{j} + \vec{v}(0), where \vec{v}(0) represents the initial velocity vector with a magnitude of v at an angle θ to \vec{i}. The solution involves constructing the initial velocity vector using trigonometric principles and integrating the velocity vector to obtain the position vector as a function of time.

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P-Jay1
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Hi, can anyone help me with this question? Or give me some helpful links. I'm stuck!

It's question B2 part b. Thanks.

View attachment PHY116.pdf
 
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What is your difficulty? You are given an acceleration vector [itex]-g\vec{j}[/itex] and, I presume, you know that the velocity vector is the integral of that [itex]-gt\vec{j}+ \vec{v}(0)[/itex] where [itex]\vec{v}(0)[/itex] is the "initial velocity" vector. You are given that by being told it has "magnitude v at an angle [itex]\theta[/itex] to [itex]\vec{i}[/itex]". Do you know how to write such a vector at that angle? (Think about the lengths of the legs of a right triangle with hypotenus of length v and one angle [itex]\theta[/itex].)

Once you have [itex]\vec{v}(0)[/itex] add it to [itex]-gt\vec{j}[/itex] to get the velocity vector as a function of t and integrate again.
 
This has answered my question. Thankyou!
 

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